我正在尝试为以下数据类型创建一个Functor实例:
data Event t a = Event { runEvent :: t -> ([a], Event t a) }
instance Functor (Event t) where
fmap :: (a -> b) -> Event t a -> Event t b
fmap f e = Event go
where
go t = (fmap f x, e')
where
(x, e') = Event.runEvent e t
但是编译失败并出现以下错误:
E FRP.fr:11: type `γ` is not as polymorphic as suggested in
the annotation where just `β` is announced.
E FRP.fr:11: type error in expression go
type is : ([γ],Event α β)
expected: ([γ],Event α γ)
我尝试添加一些类型注释来概括let绑定,但这不起作用。
答案 0 :(得分:2)
所以我们有来电e::Event t a
将runEvent
应用于e
会让我们在元组的第二个元素中仍然有Event t a
,是不是这样?但它应该是Event t b
,对吗?
(错误很混乱,因为它出现了go
并使用了在类型检查中使用的新类型变量go
)