Question

我的问题是，只要我有使用GuildName的WHERE它就不起作用。它根本不会更新任何东西只要我有id = 1（有100个公会，所以设置id = 1不是一个选项）它确实有效。

$form           = $_POST;
$boss           = $form['bossname'];
$gname          = $form['guildname'];
$screen         = $form['screenshot'];
$log            = $form['logs'];
$defeat         = $form['defeat'];

if(isset($_POST['edit-guild'])){

    $Statement = $conn->prepare("UPDATE $boss SET `Bossname` =:boss, `GuildName` =:gname, `Screenshot` =:screen, `Link` =:link, `KillTime` =:defeattime, `KillYN` =:kill WHERE `GuildName`=:gname");
    // EXECUTING ARRAY FOR ^GUILD INFORMATION
    $Statement->execute(array(
        "boss"          => $boss,
        "gname"         => $gname,
        "screen"        => $screen,
        "link"          => $log,
        "defeattime"    => $defeat,
        "kill"          => 'Yes'
        ));
}

只要我有WHERE id = 1就可以了。

 $Statement = $conn->prepare("UPDATE $boss SET `Bossname` =:boss, `GuildName` =:gname, `Screenshot` =:screen, `Link` =:link, `KillTime` =:defeattime, `KillYN` =:kill WHERE id=1");

Answer 1

如前所述，你不能重复使用相同的参数。尝试给它一个不同的名字：

if(isset($_POST['edit-guild'])){

    $Statement = $conn->prepare("UPDATE $boss SET `Bossname` =:boss, `GuildName` =:gname, `Screenshot` =:screen, `Link` =:link, `KillTime` =:defeattime, `KillYN` =:kill WHERE `GuildName`=:gname2");
    // EXECUTING ARRAY FOR ^GUILD INFORMATION
    $Statement->execute(array(
        "boss"          => $boss,
        "gname"         => $gname,
        "gname2"         => $gname,
        "screen"        => $screen,
        "link"          => $log,
        "defeattime"    => $defeat,
        "kill"          => 'Yes'
        ));
}

Answer 2

从更新集中删除gname字段。

$Statement = $conn->prepare("UPDATE $boss SET `Bossname` =:boss, `Screenshot` =:screen, `Link` =:link, `KillTime` =:defeattime, `KillYN` =:kill WHERE `GuildName`=:gname");

如果您认为gname在更新SET中很重要，您可以尝试其他不同的名称或尝试更改其他字段的位置，例如id

（PDO）UPDATE不会使用WHERE变量进行更新

2 个答案: