Question

抱歉我的英语不好，我有2个问题让我困惑。第一个问题我希望用户输入3个东西（名字，联系人，idNumber），但当我尝试输入名称时，名称输入位置丢失。我发现解决方案输入位置丢失解决方案，当用（scan.nextLine（））修复它时，另一个问题出来了，输入丢失了。第二个问题是如何将构造函数分配给数组。

public class newClient {
    Scanner scan= new Scanner(System.in);
    Random rand=new Random();
    static int IDumber;
    String unique;
    int pin;
    static int count = 0;
    private String name;
    private String idNumber;
    private String contact;

    public newClient(){
        setContact(contact);
        setIdNumber(idNumber);
        setName(name);
        count++;
    }

    public String getName(){
        return name;
    }

    public void setName(String name){
        this.name=name;  
    }

    public String getIdNumber(){
        return idNumber;   
    }

    public void setIdNumber(String idNumber){
        this.idNumber=idNumber;    
    }

    public  String getContact(){
        return contact;    
    }

    public void setContact(String contact){
        this.contact=contact;  
    }

    public  int uniqueID(){
        unique = idNumber.substring(8);
        IDumber = Integer.parseInt(unique);
        return IDumber;
    }

    public void display(){
        System.out.println("This is the password for first time login "+pin);
    }
    public int pinCode(){    
        pin = rand.nextInt(9000)+1000;   
        return pin;
    }

    public String toString(){
        return "Name: "+name+"\nUniqueID: "+IDumber+"\nContact: "+getContact()+"\npinCode: "+pin ; 
    }

    public void admin(){
        newClient []nc = new newClient[10]; 
        login();
        while(true){
            System.out.println("Select 1:add Client\n 2:add Account\n 3:login as Client");
            try{
                int selection = scan.nextInt();
                switch(selection)
                {
                case 1: addClient(nc);
                        break;
                case 2: addAccount(nc);
                        break;  
                case 3: client.client();
                        break;
                default: System.out.println("INvalid selection");
                }
            }
            catch(InputMismatchException ex){
                System.out.println("Invalid input");
                scan.nextLine();
            }
        }    
    }

    public void addClient(newClient []nc){
        newClient nw = new newClient();
        System.out.println("Enter name");
        nw.setName(scan.nextLine());
        scan.nextLine();
        System.out.println("Enter contact");
        nw.setContact(scan.nextLine());          
        System.out.println("Enter id number");
        nw.setIdNumber(scan.nextLine()); 
        nc[newClient.count]= new newClient();
        System.out.println("count"+nc[newClient.count]);   
        nw.pinCode();
        nw.uniqueID();
        System.out.println(nw.toString());
    }
}

Answer 1

首先，我不明白你在做什么以及你想要问什么。其次，我意识到你是Java的新手。虽然，你甚至不知道如何编码，我建议你在开始编码之前阅读一些材料书。你的代码有一些重要的流程和错误，其中一些我在下面纠正过。我也描述了其中一些。

java命名约定。
太多的全局变量。
必须单独创建结构文件，即（客户端）并使用它。

代码从这里开始。

import java.util.InputMismatchException;



 import java.util.Random;

import java.util.Scanner;

  `public class Client` {

    private String name;
    private String idNumber;
    private String contact;
    private String unique;
    private int pin;

    //Constructor is for initialize values and basic functionality
    public Client()
    {
        name = null;
        idNumber = null;
        contact = null;
        unique = null;
        pin = 0;
    }
    //Thats how you can interact with constructor
    public Client(String name, String idNumber, String contact, String unique, int pin)
    {
        this.name = name;
        this.idNumber = idNumber;
        this.contact = contact;
        this.unique = unique;
        this.pin = pin;
    }

    public String getName(){
        return name;
    }

    public void setName(String name){
        this.name=name;
    }

    public String getIdNumber(){
        return idNumber;   
    }

    public void setIdNumber(String idNumber){
        this.idNumber=idNumber;    
    }

    public  String getContact(){
        return contact;    
    }

    public void setContact(String contact){
        this.contact=contact;  
    }
    public  String getUnique(){
        return unique;    
    }

    public void setUnique(String unique){
        this.unique=unique;  
    }
    public int getPin(){
        return pin;  
    }
    public void setPin(int pin){
        this.pin=pin;  
    }
    @Override
    public String toString() {
        return "Client [name=" + name + ", idNumber=" + idNumber + ", contact=" + contact + ", unique=" + unique
                + ", pin=" + pin + "]";
    }

}

class NewClient
{
    public  int uniqueId(String idNumber){      
        String unique = idNumber.substring(8);
        return Integer.parseInt(unique);       
    }
public void display(int pin){
    System.out.println("This is the password for first time login "+pin);
}

public int pinCode(){
    Random rand = new Random();
    return rand.nextInt(9000)+1000;   
}

public void admin(){
    Client []nc = new Client[10];
    @SuppressWarnings("resource")
    Scanner scan = new Scanner(System.in);
    //You have somes method like login(), and i don't know what they are, so i comment rhem..
    //login();
    while(true){
        System.out.println("Select 1:add Client\n 2:add Account\n 3:login as Client");
        try{

            int selection = scan.nextInt();
            switch(selection)
            {
            case 1: nc[1] = addClient();
                    break;
            case 2: //addAccount(nc);
                    break;  
            case 3: //client.client();
                    break;
            default: System.out.println("INvalid selection");
            }
        }
        catch(InputMismatchException ex){
            System.out.println("Invalid input");
            scan.nextLine();
        }
    }    
}

public Client addClient(){
    Client client = new Client();
    Scanner scan = new Scanner(System.in);
    System.out.println("Enter name");
    client.setName(scan.nextLine());
    scan.nextLine();
    System.out.println("Enter contact");
    client.setContact(scan.nextLine());          
    System.out.println("Enter id number");
    client.setIdNumber(scan.nextLine());  
    client.setPin(pinCode());
    client.setUnique(String.valueOf(uniqueId(client.getIdNumber())));
    System.out.println(client.toString());

    return client;
}

}

我不知道，我回答你的问题，但你应该尝试这种方法！......问候

数组和输入

1 个答案: