您好我的交换功能无法正常工作我错过了什么我似乎无法找到问题,请参阅下文。提前谢谢!
<html>
<head>
<title>Three Pharagraphs</title>
<script>
function swap(a,b) {
var c = a.innerHTML;
a.innerHTML = b.innerHTML;
b.innerHTML = c;
}
window.onload = function() {
var link1 = document.getElementById('link1.1');
var link2 = document.getElementById('link2.2');
var link3 = document.getElementById('link3.3');
var p1 = document.getElementById('line1');
var p2 = document.getElementById('line2');
var p3 = document.getElementById('line3');
link1.onclick = swap(p1,p3);
link2.onclick = swap(p2,p3);
link3.onclick = swap(p1,p3);
}
</script>
</head>
<body>
<p id="line1">What is Lorem Ipsum?</p>
<p id="line2">Why do we use it?</p>
<p id="line3">The standard Lorem Ipsum passage.</p>
<p><a href="#" id="link1.1">1<->2</a> <a href="#" id="link2.2">2<->3</a><a href="#" id="link3.3">3<->1</a>
</body>
</html>
答案 0 :(得分:1)
更改link1,2和3 onclick功能,如:
link1.onclick = function() {
swap(p1,p3);
}
link2.onclick = function() {
swap(p2,p3);
}
link3.onclick = function() {
swap(p1,p3);
}
答案 1 :(得分:1)
您正在调用该函数并设置它返回到onclick的内容。你正在做的基本上是link1.onclick = undefined;
,因为该方法不会返回任何内容。
link1.onclick = function() { swap(p1,p3); }