Question

我在询问之前经常搜索（永远不够）所以我希望这不是一个重复的问题。

好吧，我走了：

我正在使用symfony开发REST API（使用FOSRestBundle和JMSSerializerBundle）。我尝试使用以下正文进行POST查询：

{
"name":"Planta 1",
"parentJoint": null,
"owner": 1,
"ownerCRUD":{
    "C":"0",
    "R":"0",
    "U":"0",
    "D":"0"
}

填写以下Doctrine的实体

<?php

    namespace AppBundle\Entity;
    use Doctrine\ORM\Mapping as ORM;

    /**
    * Joint
    *
    * @ORM\Table(name="joint")
    * @ORM\Entity(repositoryClass="AppBundle\Repository\JointRepository")
    */
    class Joint
    {

    (...)

    /**
     * @var array
     *
     * @ORM\Column(name="owner_crud", type="array",nullable = false)
     */
    private $ownerCRUD;

    /** 
     * Set ownerCRUD
     *
     * @param array $ownerCRUD
     * @return Joint
     */
    public function setOwnerCRUD($ownerCRUD)
    {
        $this->ownerCRUD = $ownerCRUD;        
        return $this;
    }

    /**
     * Get ownerCRUD
     *
     * @return array 
     */
    public function getOwnerCRUD()
    {
        return $this->ownerCRUD;
    }

    public function __toString() 
    {
        return 'any string';
    }
}

我尝试通过此控制器的功能：

 /**
 * Description: This method create and persist in database a new Joint Element
 * 
 * @ApiDoc(
 * )
 *
 * @var Request $request    
 */
public function postJointAction(Request $request)
{ 
    try {
        $parameters = $request->request->all();
        dump($parameters);
        $joint = new Joint();
        $form = $this->createForm('AppBundle\Form\JointType', $joint);
        $form->submit($parameters, 'POST');
        dump($form);
        if ($form->isValid()) {
            $em = $this->getDoctrine()->getManager();
            $joint = $form->getData();
            $em->persist($joint);
            $em->flush($joint);
            $joint = $em->getRepository('AppBundle:Joint')->find($joint->getId());        
            //Create a View
            $templateData = array('joint' => $joint);
            $view = $this->view($templateData,200)
            ->setTemplate("joint/show.html.twig")
            ->setTemplateVar('joint')
            ->setTemplateData($templateData)
            ->setData($templateData)
        ;
        return $this->handleView($view);
        }                     
    } catch (InvalidFormException $exception) {
        return $exception->getForm();            
    }
}

我的表格是这样的：

<?php

namespace AppBundle\Form;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolver;

class JointType extends AbstractType
{
    /**
     * {@inheritdoc}
     */
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
        ->add('name')
        ->add('parentJoint')
        ->add('owner')
        ->add('ownerCRUD') ;
    }

    /**
     * {@inheritdoc}
     */
    public function configureOptions(OptionsResolver $resolver)
    {
        $resolver->setDefaults(array(
            'data_class' => 'AppBundle\Entity\Joint',
            'csrf_protection' => false
        ));
    }

    /**
     * {@inheritdoc}
     */
    public function getBlockPrefix()
    {
        return 'appbundle_joint';
    }

    /**
     * @return string
     */
    public function getName()
    {
        return "";
    }
}

问题是表单没有正确获取ownerCRUD字段，表单假设是额外的字段而不是正确的字段

This form should not contain extra fields.  ownerCRUD   
Symfony\Component\Validator\ConstraintViolation
Object(Symfony\Component\Form\Form).children[ownerCRUD] = [C => 0, R => 0, U => 0, D => 0]

提前致谢

我的枝条文件

{% extends 'base.html.twig' %}

{% block body %}
<h1>Joint</h1>

<table>
    <tbody>
        <tr>
            <th>Id</th>
            <td>{{ joint.id }}</td>
        </tr>
        <tr>
            <th>Name</th>
            <td>{{ joint.name }}</td>
        </tr>
    </tbody>
</table>

<ul>
    <li>
        <a href="{{ path('get_joints') }}">Back to the list</a>
    </li>
    <li>
        <a href="{{ path('put_joint', { 'joint': joint.id }) }}">Edit</a>
    </li>
</ul>
{% endblock %}

Answer 1

你的身体对我来说似乎无效。由于ownerCRUD应该是一个数组，你的身体应该是这样的：

{
    "name":"Planta 1",
    "parentJoint": null,
    "owner": 1,
    "ownerCRUD":[
        "0",
        "0",
        "0",
        "0"
    ]
}

注意[]而不是{}围绕＆＃34; C＆＃34;：＆＃34; 0＆＃34;，＆＃34; R＆＃34;：＆＃34; 0＆＃34;，＆＃ 34; U＆＃34;：＆＃34; 0＆＃34;，＆＃34; D＆＃34;：＆＃34; 0＆＃34;

修改

删除了密钥＆＃34; C＆＃34;，＆＃34; R＆＃34;，＆＃34; U＆＃34;，＆＃34; D＆＃34;

Answer 2

我建议你改变你的实体..

我的替代方案：

将“ownerCRUD”的数据类型转换为字符串值..

联合实体：

 /**
     * @var array
     *
     * @ORM\Column(name="owner_crud", type="string",nullable = false)
     */
    private $ownerCRUD;


    /** 
     * Set ownerCRUD
     *
     * @param array $ownerCRUD
     * @return Joint
     */
    public function setOwnerCRUD(array $ownerCRUD)
    {
        $this->ownerCRUD = $ownerCRUD;
        return $this;
    }

    /**
     * Get ownerCRUD
     *
     * @return array 
     */
    public function getOwnerCRUD()
    {
        return array($this->ownerCRUD);
    }

提交数组类型Doctrine表单

2 个答案: