Question

我尝试使用我创建的类中的get方法，错误说

＆＃34;可捕获的致命错误：无法将类IdmoreRO的对象转换为＆＃34;

中的字符串

当我尝试使用魔术方法__toString（）时，它的错误也说

致命错误：方法IdmoreRO :: __ tostring（）无法接受中的参数

这是我的代码：

idmore.php

class IdmoreRO
{
    public function __construct()
    {
    }

    //hitung ongkir
    public function __toString($origin,$destination,$weight,$courier)
    {
        $curl = curl_init();
        curl_setopt_array($curl, array(
            CURLOPT_URL => "http://rajaongkir.com/api/starter/cost",
            CURLOPT_RETURNTRANSFER => true,
            CURLOPT_ENCODING => "",
            CURLOPT_MAXREDIRS => 10,
            CURLOPT_TIMEOUT => 30,
            CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
            CURLOPT_CUSTOMREQUEST => "POST",
            CURLOPT_POSTFIELDS => "origin=$origin&destination=$destination&weight=$weight&courier=$courier",CURLOPT_HTTPHEADER => array("key: $this-> 3f01f13ce2b42ba983ad3f3bc4852f84"),
        ));
        $response = curl_exec($curl);
        $err = curl_error($curl);
        curl_close($curl);
        if ($err) {
            $result = 'error';
            return 'error';
        } else {
            return $response;
        }
    }
}

process.php

#header("Content-Type: application/x-www-form-urlencoded");
require_once('idmore.php');

$IdmoreRO = new IdmoreRO();
if(isset($_GET['act'])):

        switch ($_GET['act']) {

        case 'showprovince':
            $province = $IdmoreRO->showProvince();
            echo $province;

        break;

        case 'showcity':
            $idprovince = $_GET['province'];
            $city = $IdmoreRO->showCity($idprovince);
            echo $city;

        break;

        case 'cost':
            $origin = $_GET['origin'];
            $destination = $_GET['destination'];
            $weight = $_GET['weight'];
            $courier = $_GET['courier'];
            $cost = $IdmoreRO->__toString($origin,$destination,$weight,$courier);
            echo $cost;
            break;

        }
endif;

Answer 1

正如错误消息所示，__toString无法接收任何参数

你可能会做这样的事情

class IdmoreRO
{
    private $origin;
    private $destination;
    private $weight;
    private $courier;

    public function __construct(
        $origin,
        $destination,
        $weight,
        $courier
    ) {
        $this->origin = $origin;
        $this->destination = $destination;
        $this->weight = $weight;
        $this->courier = $courier;
    }

    public function __toString()
    {
        // use $this->origin, $this->destination, $this->weight and $this->courier
    }
}

PHP错误对象无法转换为字符串

1 个答案: