Question

我在我的应用程序中使用Alamofire进行网络连接。在Alamofire中，我正在编写POST方法将值传递给url，但它没有传递任何值。显示为null。以下是我的代码：

<input type="button" value="Submit" onclick="changeConfirmed(json_encode($result))">

如果有人弄错了我做错了什么。谢谢!!

Answer 1

您使用的是哪种版本的alamofire？请尝试使用URLEncoding.default而不是JSONEncoding.default。

Answer 2

试试这样：

let url = NSURL（string：URLName）

让request = NSMutableURLRequest（URL：url！）

request.HTTPMethod =“POST”

request.setValue（“application / json”，forHTTPHeaderField：“Content-Type”）

让data =试试！ NSJSONSerialization.dataWithJSONObject（参数！，选项：NSJSONWritingOptions.PrettyPrinted）

让json = NSString（数据：数据，编码：NSUTF8StringEncoding）如果让json = json { 打印（JSON） }

      request.HTTPBody = json!.dataUsingEncoding(NSUTF8StringEncoding);


            Alamofire.request(request)
                .responseString { response in
                    // do whatever you want here
                    print(response.result)
                    switch (response.result) {
                    case .Success(let JSON):
                       print(JSON)
                    case .Failure: break

                    }
            }

Answer 3

我使用swift2.3并使用Alamofire ..它对我有用：

class APIUtils: NSObject{static func fetchData(requestModel:RequestModel,completionBlock:(response:ResponseModel)->Void){

    let url = "\(requestModel.baseUrl)\(requestModel.apiUrl)"

    Alamofire.request(APIUtils().getHTTPMethod(requestModel.httpMethodType), url, parameters: requestModel.parametersDict,headers:requestModel.headersDict,encoding:(APIUtils().getEncodingFormat(requestModel.encodeType))).responseJSON { (responseObj) -> Void in

        let responseModel = ResponseModel()
        responseModel.responseCode = responseObj.response?.statusCode

        switch responseObj.result {
            case .Success(let data):
                if (data .isKindOfClass(NSDictionary)){
                    responseModel.responseDictionary = data as! NSDictionary
                }else if (data .isKindOfClass(NSArray)){
                    responseModel.customModel = data as! NSArray
                }
                responseModel.isSuccess = true
                break

            case .Failure(let error):

                responseModel.isSuccess = false

                print("Request failed with error: \(error)")
                break
        }

        completionBlock(response: responseModel)
    }
}

func getHTTPMethod(methodType:HTTPMethodType)->Alamofire.Method{
    switch(methodType){
        case .GET: return Alamofire.Method.GET
        case .POST: return Alamofire.Method.POST
        case .PUT: return Alamofire.Method.PUT
        case .PATCH: return Alamofire.Method.PATCH
        case .DELETE: return Alamofire.Method.DELETE

    }
}
func getEncodingFormat(methodType:encodingType)->Alamofire.ParameterEncoding{
    switch(methodType){
    case .URL: return Alamofire.ParameterEncoding.URL
    case .JSON: return Alamofire.ParameterEncoding.JSON
    case .URLEncodedInURL: return Alamofire.ParameterEncoding.URLEncodedInURL

    }
}

}

//试试这个：

let urlencode = Alamofire.ParameterEncoding
    print(MyStrings.BaseURl+urlString)
    Alamofire.request(action, MyStrings.BaseURl+urlString, headers: headers, parameters:urlParams, encoding: isBody == true ? urlencode.JSON : urlencode.URLEncodedInURL)
        .validate(statusCode: 200..<300)
        .responseJSON { responseO in
            if (responseO.result.error == nil) {
                let responseModel = ResponseModel()
                responseModel.responseCode = responseO.response?.statusCode

                switch responseO.result {
                case .Success(let data):
                    if (data .isKindOfClass(NSDictionary)){
                        responseModel.responseDictionary = data as! NSDictionary
                    }else if (data .isKindOfClass(NSArray)){
                        responseModel.customModel = data as! NSArray
                    }
                    responseModel.isSuccess = true
                    break
                case .Failure(let error):
                    responseModel.isSuccess = false
                    print("Request failed with error: \(error)")
                    break
                }
                completionBlock(response: responseModel)
            }
            else {
                debugPrint("HTTP Request failed: \(responseO.result.error?.userInfo)")
                let responseModel = ResponseModel()
                responseModel.responseCode = responseO.response?.statusCode
                responseModel.isSuccess = false
                completionBlock(response: responseModel)
            }
    }

Alamofire POST方法没有将值传递给url

3 个答案: