逐字阅读数据

Question

我有一个数据列表，我试图将字符存储在一个整数数组中，并将小数存储在双精度数组中。问题是：如果不阅读整条线，你怎么做？我想也许可以问是否有空间，停止阅读。但考虑到有多条线路，我该如何做呢？这是数据：

A 0.08030130328545595500
B 0.01404566680148545800
C 0.02309245337888202900
D 0.04680329046987134100
E 0.12475974957130967000
F 0.02262448732647651800
G 0.02092142515718645500
H 0.06495870199587520900
I 0.06832638626586488900
J 0.00118328558965393900
K 0.00796545073487383260
L 0.03678714564106335500
M 0.02553256208071077300
N 0.07071134182580297900
O 0.07759211410349403600
P 0.01653257210855475400
Q 0.00111309068179311220
R 0.06200383063640040700
S 0.06269909448568859700
T 0.09005003894146078300
U 0.02792921679195900500
V 0.00865068674018190480
W 0.02356209073861756000
X 0.00115988728703366340
Y 0.02033479628434954300
Z 0.00035933107595423293

Answer 1

像这样

#include <stdio.h>
#include <stdlib.h>

int main(void){
    int ch[32] = {0};
    double num[32];
    char word[32];
    int i = 0, n, flipflop = 0;

    while(1 == scanf("%31s", word)){//read word by word
        if(flipflop){
            num[i++] = atof(word);
        } else {
            if(*word && !word[1]){//a character
                ch[i] = *word;
            }
        }
        flipflop = !flipflop;
    }
    n = i;
    for(i = 0; i < n; ++i){//test print
        printf("%c %.20f\n", ch[i], num[i]);
    }
    return 0;
}