在这个程序中,我创建了一个通用链表.Insert和Display函数工作正常但是union函数没有工作。我实际上不确定我写的函数是否正确,我该如何执行两个给定清单的联合。
import java.util.*;
class Node<T> {
T data;
Node<T> next;
Node(T d) {
data = d;
}
void display() {
System.out.println(data + " ");
}
}
class List<T> {
Node<T> first;
List() {
first = null;
}
void insert(T data) {
Node<T> newnode = new Node<T>(data);
if (first == null)
first = newnode;
else {
Node<T> temp = first;
while (temp.next != null)
temp = temp.next;
temp.next = newnode;
}
}
void display() {
if (first == null)
System.out.println("EmpTY");
else {
Node<T> temp = first;
while (temp != null) {
temp.display();
temp = temp.next;
}
}
}
public void union(Node<Double> head1, Node<Double> head2) {
Node<T> t = head1;
Node<T> t1 = head2;
while (t != null && t1 != null) {
if (t.data > t1.data) {
System.out.println(t.data + "\n");
t = t.next;
} else if (t.data < t1.data) {
System.out.println(t1.data + "\n");
t1 = t1.next;
} else {
System.out.println(t.data + "\n");
System.out.println(t.data + "\n");
t = t.next;
t1 = t1.next;
}
}
}
}
class DEMO {
public static void main(String args[]) {
List<Double> l1 = new List<Double>();
for (double i = 0; i < 5; i++) {
l1.insert(i);
}
l1.display();
List<Double> l2 = new List<Double>();
List<Double> l3 = new List<Double>();
for (double j = 0; j < 5; j++) {
l2.insert(j);
}
l3.union(l1, l2);
}
}
答案 0 :(得分:-1)
您可以这样做:
/* Function to get Union of 2 Linked Lists */
void doUnion(Node head1, Node head2) {
Node t1 = head1, t2 = head2;
//insert all elements of list1 in the result
while (t1 != null) {
push(t1.data);
t1 = t1.next;
}
// insert those elements of list2 that are not present
while (t2 != null) {
if (!isPresent(head, t2.data)) {
push(t2.data);
}
t2 = t2.next;
}
}
/* Inserts a node at start of linked list */
void push(int new_data) {
/* 1. Allocate the Node & Put in the data*/
Node new_node = new Node(new_data);
/* 2. Make next of new Node as head */
new_node.next = head;
/* 3. Move the head to point to new Node */
head = new_node;
}
/* A utilty function that returns true if data is present in linked list else return false */
boolean isPresent(Node head, int data) {
Node t = head;
while (t != null) {
if (t.data == data) {
return true;
}
t = t.next;
}
return false;
}