LinearLayout中的Android ScrollView

Question

Andoid中的布局（按钮）有问题。我想要的是在ScrollView中显示按钮，但ScrollView必须在RelativeLayout之下，或者换句话说，ScrollView的前两个按钮不会显示在我的手机上..

这是图片：

这是我的布局：

SQL = "Select Top 1 SomeTextField From Sites Where H2OBillingIDNum = ...

如何在文字下方展示ScrollView＆＃34; morska bioloska postaja ...＆＃34;？

谢谢

Answer 1

您需要从android:layout_gravity="center"内的LinearLayout移除ScrollView。您可能还想删除其android:paddingTop="90.0dip"。

Answer 2

将此内容添加到您的滚动视图中：

android:layout_height="fill_parent"

这应该在textView下面添加滚动，并删除它：

android:layout_height="wrap_content"

并替换为：

<input type="file" name="attach" id="attach-input" multiple="" style="display:none" />
<button type="submit" name="attach" id="attach-button">Upload</button>

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<script>

    var button = $('#attach-button');
    var input = $('#attach-input');

    // translates collection of files into a form
    function BuildFormData(files) {

        var data = new FormData();

        for (var i = 0; i < files.length; i++) {

            data.append(files[i].name, files[i]);
        }

        return data;
    }

    // posts the files to a given url
    function PostData(url, data) {

        $.ajax({
            // method
            type: 'POST',

            // endpoint
            url: url,

            // next 2 lines required for using FormData with jQuery
            contentType: false,
            processData: false,

            // FormData instance
            data: data,

            // success handler
            success: function (result) {

                alert('files uploaded successfully');

                console.log(result);
            }
        });
    }

    // when the button is clicked..
    button.on('click', function (e) {

        // it launches the file picker
        input.click();
    });

    // when the file picker changes..
    input.on('change', function (e) {

        // turn it into a form
        var data = BuildFormData(e.target.files);

        // post the form to the action method
        PostData('/Index/Attach', data);
    });

</script>