我有一个数组:
[{"IDAlokasiEmiten":154,"IDOrganization":12,"NamaOrganization":null,"CodeEmiten":"ANTM","NameEmiten":"AAneka Tambang (Persero) Tbk"},{"IDAlokasiEmiten":0,"IDOrganization":null,"NamaOrganization":null,"CodeEmiten":"ADHI","NameEmiten":"Adhi Karya (Persero) Tbk"}]
如何在发布到API之前更改某些值?
我希望POST到API:
[{"IDAlokasiEmiten":0,"IDOrganization":12,"NamaOrganization":null,"CodeEmiten":"ANTM","NameEmiten":"AAneka Tambang (Persero) Tbk"},{"IDAlokasiEmiten":0,"IDOrganization":12,"NamaOrganization":null,"CodeEmiten":"ADHI","NameEmiten":"Adhi Karya (Persero) Tbk"}]
这是我的AngularJS:
// GET Detail Alokasi Emiten
$scope.emit.detailDaftarEmiten = [];
$scope.addItemAlokasi = function () {
$scope.emit.detailDaftarEmiten.push({
IDAlokasiEmiten: 0,
IDOrganization: 12,
NamaOrganization: '',
CodeEmiten: $scope.emit.detailDaftarEmiten.CodeEmiten,
NameEmiten: $scope.emit.detailDaftarEmiten.NameEmiten
});
$scope.emit.detailDaftarEmiten.IDAlokasiEmiten = '';
$scope.emit.detailDaftarEmiten.IDOrganization = '';
$scope.emit.detailDaftarEmiten.NamaOrganization = '';
$scope.emit.detailDaftarEmiten.CodeEmiten = '';
$scope.emit.detailDaftarEmiten.NameEmiten = ''
};
$scope.resetForm = function () {
$scope.emit.detailDaftarEmiten.IDAlokasiEmiten = '';
$scope.emit.detailDaftarEmiten.IDOrganization = '';
$scope.emit.detailDaftarEmiten.NamaOrganization = '';
$scope.emit.detailDaftarEmiten.CodeEmiten = '';
$scope.emit.detailDaftarEmiten.NameEmiten = ''
};
$scope.deleteItem = function (index) {
$scope.emit.detailDaftarEmiten.splice(index, 1);
};
$scope.getTotalItems = function () {
return $scope.detailDaftarEmiten.length;
};
但它不起作用:(
我想为(IDAlokasiEmiten=0
和IDOrganization=12
)设置所有值数组。
答案 0 :(得分:0)
var obj=your code;
obj[0]["IDOrganisation"]=12;
//0 -> first object in array
这是简单的javascript。您应该访问MDN并了解更多信息......
答案 1 :(得分:0)
是的,你可以使用普通的javascript而不使用forEach
方法的库来做到这一点。
arr=[{"IDAlokasiEmiten":154,"IDOrganization":12,"NamaOrganization":null,"CodeEmiten":"ANTM","NameEmiten":"AAneka Tambang (Persero) Tbk"},{"IDAlokasiEmiten":0,"IDOrganization":null,"NamaOrganization":null,"CodeEmiten":"ADHI","NameEmiten":"Adhi Karya (Persero) Tbk"}]
arr.forEach(function(a){
a["IDAlokasiEmiten"]=0;
a["IDOrganization"]=12;
});
console.log(arr);
答案 2 :(得分:0)
您可以尝试以下声明。
var arr = [{"IDAlokasiEmiten":154,"IDOrganization":12,"NamaOrganization":null,"CodeEmiten":"ANTM","NameEmiten":"AAneka Tambang (Persero) Tbk"},{"IDAlokasiEmiten":0,"IDOrganization":null,"NamaOrganization":null,"CodeEmiten":"ADHI","NameEmiten":"Adhi Karya (Persero) Tbk"}];
arr.map(i=>{i.IDAlokasiEmiten=0;i.IDOrganization=12;})
答案 3 :(得分:0)
var a = [{"IDAlokasiEmiten":154,"IDOrganization":12,"NamaOrganization":null,"CodeEmiten":"ANTM","NameEmiten":"AAneka Tambang (Persero) Tbk"},{"IDAlokasiEmiten":0,"IDOrganization":null,"NamaOrganization":null,"CodeEmiten":"ADHI","NameEmiten":"Adhi Karya (Persero) Tbk"}];
a.forEach(function(e) {
e.IDAlokasiEmiten = 0;
e.IDOrganization = 12;
});
JSON.stringify(a);
答案 4 :(得分:0)
首先,它的json数据。
您必须首先反序列化,然后序列化回json。
maven-antrun-plugin
使用NewtonSoft.Json dll。
您可以将此json反序列化为public class Sample
{
public int IDAlokasiEmiten { get; set; }
public int? IDOrganization { get; set; }
public object NamaOrganization { get; set; }
public string CodeEmiten { get; set; }
public string NameEmiten { get; set; }
}
,然后遍历它并设置每个对象的属性。
<强> JSON 强>
SampleClass[]
C#代码:
[{
"IDAlokasiEmiten": 154,
"IDOrganization": 12,
"NamaOrganization": null,
"CodeEmiten": "ANTM",
"NameEmiten": "AAneka Tambang (Persero) Tbk"
}, {
"IDAlokasiEmiten": 0,
"IDOrganization": null,
"NamaOrganization": null,
"CodeEmiten": "ADHI",
"NameEmiten": "Adhi Karya (Persero) Tbk"
}]