如何在for循环中执行多个数据子集

时间:2016-11-17 12:56:47

标签: r for-loop plot

我有10个时间点(行)的300个变量(列),对于每个变量,在任何给定的时间点,我都有温度值A和F.所以在我的数据帧上,我有2行用于A + F的时间点1,所以上

这是我可重复的例子

Timepoint <- c('1','1','2','2','3','3')
Temperature <- c('A','F','A','F','A','F')
Cholesterol <- c('1','2','3','2','3','4')

data.frame(Timepoint,Temperature,Cholesterol)

这是我的实际数据样本

 structure(list(Timepoint = c(1L, 1L, 2L, 2L, 3L, 3L, 4L, 4L, 
  5L, 5L, 6L, 6L, 7L, 7L, 8L, 8L, 9L, 9L, 13L, 13L, 25L, 25L), 
     Temperature = structure(c(1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 
     1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L), .Label = c("A", 
    "F"), class = "factor"), Concentration.of.chylomicrons = c(1.29e-11, 
    1.25e-11, 1.02e-11, 1.1e-11, 1.08e-11, 1.3e-11, 1.28e-11, 
    1.26e-11, 1.06e-11, 1.32e-11, 8.85e-12, 1.21e-11, 8.83e-12, 
    1.08e-11, 1.35e-11, 1.12e-11, 8.99e-12, 1.08e-11, 9.55e-12, 
    1.04e-11, 0, 1.01e-11), Total.lipids = c(0.00268, 0.0026, 
    0.00208, 0.00225, 0.00222, 0.0027, 0.00268, 0.0026, 0.00219, 
    0.00273, 0.0018, 0.00247, 0.00179, 0.00221, 0.00276, 0.00229, 
     0.00182, 0.00222, 0.00195, 0.00212, 0, 0.00204), Phospholipids = c(0.000224, 
    0.000223, 0.000145, 0.00016, 0.000157, 0.000211, 0.00023, 
    0.000211, 0.000165, 0.000224, 0.000109, 0.00018, 0.000113, 
    0.000163, 0.000175, 0.000177, 0.000122, 0.000173, 0.000127, 
    0.000156, 0, 0.000138)), .Names = c("Timepoint", "Temperature", 
"Concentration.of.chylomicrons", "Total.lipids", "Phospholipids"
), class = "data.frame", row.names = c(NA, -22L))

我想绘制一个折线图,以显示每个变量如何随时间变化。在这个折线图上,我希望绘制A和B线

我已设法使用以下代码执行此操作

plot(DATA$Timepoint[DATA$Temperature=="F"],DATA$variable[DATA$Temperature=="F"])

lines(DATA$Timepoint[DATA$Temperature=="F"],DATA$Cvariable[TempMline$Temperature=="A"])

这给出了变量如何随时间变化的曲线图,每个温度A + F都有一条单独的线。

我正在尝试编写一个循环命令来绘制每个变量的图形,尽管我在使用[]子集数据时遇到了问题,并且还编写了循环命令

这是我的尝试

lnames <- names(DATA)
classes<-sapply(DATA,class)

for(name in lnames[classes == 'numeric']) {

 plot(DATA$Timepoint[DATA$Temperature=="F"],DATA$[,name][DATA$Temperature=="F"])
 lines(DATA$Timepoint[DATA$Temperature=="F"],DATA$[,name][TempMline$Temperature=="A"]) }

1 个答案:

答案 0 :(得分:1)

这是你正在寻找的吗?我只显示最后一张图,因为这是循环的结束。如果你正在使用RStudio,你可以在情节查看器中切换左/右箭头键。

enter image description here

这是绘图和循环的代码:

# subset based on temperatures A and F
a_df <- subset(df, Temperature == "A")
f_df <- subset(df, Temperature == "F")

# loop from columns 3:5 (or for the number of variables you have)
for (i in 3:5) {
      plot(a_df[, 1], 
           a_df[, i], 
           type = "l",
           ylab = colnames(a_df[i]),
           xlab = "Timepoint",
           lwd = 2,
           col = "blue")
      lines(f_df[, 1],
            f_df[, i],
            type = "l",
            lwd = 2,
            col = "red")
      legend("bottomleft", 
             col = c("blue", "red"), 
             legend = c("Temperature A", "Temperature F"), 
             lwd = 2,
             y.intersp = 0.5,
             bty = "n")
}
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