Question

我正在尝试使用Xamp Server从数据库中获取数据，但我收到此错误。

致命错误：未捕获错误：调用未定义的函数 E：\ xamp \ htdocs \ PoliceApp \ News \ fetch.php中的mysql_select_db（）：10 Stack trace：＃0 {main}抛出E：\ xamp \ htdocs \ PoliceApp \ News \ fetch.php on 第10行

下面是我的 php 脚本，我仍然是 php 的新手，请帮我解决这个问题。但是我在这里阅读了所有其他帖子，但这似乎让我感到困惑，我怎么能把它做好。

<?php  
$username="root";  
$password="namungoona";  
$hostname = "localhost";  
//connection string with database  
$dbhandle = mysqli_connect($hostname, $username, $password)  
or die("Unable to connect to MySQL");  
echo "";  
// connect with database  
$selected = mysql_select_db("police",$dbhandle)  
or die("Could not select examples");  
//query fire  
$result = mysql_query("select * from News;");  
$json_response = array();  
// fetch data in array format  
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {  
// Fetch data of Fname Column and store in array of row_array
$row_array['Headlines'] = $row['Headlines'];  
$row_array['Details'] = $row['Details']; 
$row_array['NewsPhoto'] = $row['NewsPhoto']; 

//push the values in the array  
array_push($json_response,$row_array);  
}  
//  
echo json_encode($json_response);  
?>

Answer 1

根据您的要求，我修改了代码。

<?php  
$username="root";  
$password="namungoona";  
$hostname = "localhost";  
//connection string with database  
$dbhandle = mysqli_connect($hostname, $username, $password)  
or die("Unable to connect to MySQL");  
echo "";  
// connect with database  
$selected = mysqli_select_db($dbhandle, "police")  
or die("Could not select examples");  
//query fire  
$result = mysqli_query($dbhandle,"select * from News;");  
$json_response = array();  
// fetch data in array format  
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {  
// Fetch data of Fname Column and store in array of row_array
$row_array['Headlines'] = $row['Headlines'];  
$row_array['Details'] = $row['Details']; 
$row_array['NewsPhoto'] = $row['NewsPhoto']; 

//push the values in the array  
array_push($json_response,$row_array);  
}  
//  
echo json_encode($json_response); 
mysqli_free_result($result);
?>

请注意：您需要添加错误检查。另请注意只需键入此处（未经测试），如果有错误，请耐心等待。

Answer 2

只需在php代码中将mysql更改为myqsli，因为XAMPP（我想）正在正确读取SQLi而不是SQL

未捕获的错误：调用未定义的函数mysql_select_db（）

2 个答案: