Question

我正在开发一个需要返回树中所有叶子（文件）列表的项目。我不知道如何开始，我需要一些帮助：）

我需要创建一个程序来返回运行进程（my_program.py）的当前文件夹中的所有文件和文件夹，结果应包含根文件夹，文件，子文件夹和子文件夹。文件等....

Answer 1

import os
##Provide value of a path in filepath variable
filepath="C:\Users\poonamr\Desktop"
for path, dirs, files in os.walk(os.path.abspath(filepath)):
    print path
    if len(dirs)==0:
        print('No directories available in "' + path + '"')
    else:
        print dirs
    if len(files)==0:
        print('No files available in "' + dirs + '"') 
    else:
        print files
    print "\n"

Answer 2

import os

def FileTree(Original_Path):
    dirlist=[]
    filelist=[]
    for dirnm in os.listdir(Original_Path):
        if os.path.isdir(Original_Path + "\\" + dirnm):
            dirlist.append(dirnm)
        else:
             filelist.append(dirnm)
    print "Folder    : " , Original_Path
    print "SubFolder : " , dirlist
    print "Files     : " , filelist
    print "\n\n"
    for dirSub in dirlist:
        FileTree(Original_Path+ "\\" + dirSub + "\\")


##Path specification    
Original_Path="C:\Users\poonamr\Desktop\Python Programs"
FileTree(Original_Path)

如何使用python实现分层树？

2 个答案: