Question

我有一个日期数组。在加载时我想用Moment JS解析这些日期，然后在myTable的B列中显示这些日期。

到目前为止，我已经将数组的最后一个值返回3次，我不知道为什么。

function loadFunction () {

    var cellData = ["2016-08-24 12:45", "2016-08-24 16:00","2016-08-24 13:00"];

    var myTable = document.getElementById("myTable");

    var times = [];

    for (var i =0; i <cellData.length; i++) {

        var date = moment(cellData[i]).format('MM/DD/YYYY hh:mm a');
        times.push(date);

    for (var j=1; j < 6 ; j+=2) {

        myTable.rows[j].cells[1].innerHTML = times[i];

        }
    }
}


<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.15.1/moment.min.js"></script>

<body onload="loadFunction()">

<table id="myTable">
    <thead>
        <tr>
            <th colspan="3">Table</th>
        </tr>
    </thead>
    <tbody>
        <tr>
            <td>A</td>
            <td>B</td>
            <td>C</td>
        </tr>
        <tr style="display:none;">
            <td colspan="3"></td>
        </tr>
        <tr>
            <td>A</td>
            <td>B</td>
            <td>C</td>
        </tr>
        <tr style="display:none;">
            <td colspan="3"></td>
        </tr>
        <tr>
            <td>A</td>
            <td>B</td>
            <td>C</td>
        </tr>
        <tr style="display:none;">
            <td colspan="3"></td>
        </tr>
</tbody>
</body>

Answer 1

您的第二个for为每个值迭代3次。因此，在单元格的最后一个值，它将设置为单元格1 3和5相同的值。尝试在for之外声明变量，并在迭代之后更改j

的值

＆＃13;

function loadFunction () {

    var cellData = ["2016-08-24 12:45", "2016-08-24 16:00","2016-08-24 13:00"];

    var myTable = document.getElementById("myTable");

    var times = [];
    var j=1;
  
    for (var i =0; i <cellData.length; i++) {

        var date = moment(cellData[i]).format('MM/DD/YYYY hh:mm a');
        times.push(date);

        myTable.rows[j].cells[1].innerHTML = times[i];
        j += 2;
         
    }
}

＆＃13;

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.15.1/moment.min.js"></script>

<body onload="loadFunction()">

<table id="myTable">
    <thead>
        <tr>
            <th colspan="3">Table</th>
        </tr>
    </thead>
    <tbody>
        <tr>
            <td>A</td>
            <td>B</td>
            <td>C</td>
        </tr>
        <tr style="display:none;">
            <td colspan="3"></td>
        </tr>
        <tr>
            <td>A</td>
            <td>B</td>
            <td>C</td>
        </tr>
        <tr style="display:none;">
            <td colspan="3"></td>
        </tr>
        <tr>
            <td>A</td>
            <td>B</td>
            <td>C</td>
        </tr>
        <tr style="display:none;">
            <td colspan="3"></td>
        </tr>
</tbody>
</body>

＆＃13;

嵌套for循环返回错误的值

1 个答案: