Question

我有一个正则表达式，用于检查字符串是否为URL：

const regex = /(http|https):\/\/(\w+:{0,1}\w*)?(\S+)(:[0-9]+)?(\/|\/([\w#!:.?+=&%!\-\/]))?/

我试过了：

const regex = '/(http|https):\/\/(\w+:{0,1}\w*)?(\S+)(:[0-9]+)?' + // eslint-disable-line
'(\/|\/([\w#!:.?+=&%!\-\/]))?/' // eslint-disable-line

但正则表达式不再匹配了。同样的：

const regex = new RegExp(['/(http|https):\/\/(\w+:{0,1}\w*)?(\S+)(:[0-9]+)?', // eslint-disable-line
'(\/|\/([\w#!:.?+=&%!\-\/]))?/'].join('')) // eslint-disable-line

这样做的正确方法是什么？

修改

示例字符串：http://vrcam-10065475.image.myqcloud.com/7a88620cb5ec7eb90164.jpg?imageView2/2/w/600/h/600/q/100/format/jpg

Answer 1

试试：

var regex = RegExp(
  "(http|https)://(\\w+:{0,1}\\w*)?(\\S+)(:[0-9]+)?" +
  "(/|/([\\w#!:.?+=&%!-/]))?"
);

Run the sample here

如何正确地将这个正则表达式分成两行？

1 个答案: