Question

在我不断寻求完成我的tic tac toe游戏时，我尝试编写一个功能来检查获胜者。游戏看起来像这样：董事会由一系列清单组成：

lst = ['1','2','3','4','5','6','7','8','9']

def board():
print (lst[0:3])
print (lst[3:6])
print (lst[6:])

['1', '2', '3']
['4', '5', '6']
['7', '8', '9']

then this not so elegant function to check for a winner: 

def conclusion():
if all('o' == item for item in (lst[0],lst[1],lst[2])):
    print('Player 2 wins!')
elif all('o' == item for item in (lst[3],lst[4],lst[5])):
    print('Player 2 wins!')
elif all('o' == item for item in (lst[6],lst[7],lst[8])):
    print('Player 2 wins')
elif all('o' == item for item in (lst[0],lst[3],lst[6])):
    print('Player 2 wins')
elif all('o' == item for item in (lst[1],lst[4],lst[7])):
    print('Player 2 wins')
elif all('o' == item for item in (lst[3],lst[6],lst[9])):
    print('Player 2 wins')
elif all('o' == item for item in (lst[0],lst[4],lst[8])):
    print('Player 2 wins')
elif all('o' == item for item in (lst[2],lst[4],lst[6])): 
    print('Player 2 wins')
elif all('x' == item for item in (lst[0],lst[1],lst[2])):
    print('Player 1 wins!')
elif all('x' == item for item in (lst[3],lst[4],lst[5])):
    print('Player 1 wins!')
elif all('x' == item for item in (lst[6],lst[7],lst[8])):
    print('Player 1 wins')
elif all('x' == item for item in (lst[0],lst[3],lst[6])):
    print('Player 1 wins')
elif all('x' == item for item in (lst[1],lst[4],lst[7])):
    print('Player 1 wins')
elif all('x' == item for item in (lst[3],lst[6],lst[9])):
    print('Player 1 wins')
elif all('x' == item for item in (lst[0],lst[4],lst[8])):
    print('Player 1 wins')
elif all('x' == item for item in (lst[2],lst[4],lst[6])): 
    print('Player 1 wins')
else:
    pass

然后是游戏玩法的这些功能：

def move2():
conclusion()
move2=(input('Player 2: Type a number!'))
for x in lst:
    if move2 == x:
        lst[int(move2)-1] = 'o'
        board()
        move()
    elif move2.isdigit() and move2 not in lst:
        print('Not that number dipshit!')
        break
        board()
        move2()
    elif not move2.isdigit():
        print('Not that number dipshit!')
        break
        board()
        move2()


def move():
conclucion()
move1=(input('Player 1: Type a number!'))
for x in lst:
    if move1 == x:
        lst[int(move1)-1] = 'x'
        board()
        move2()
    elif move1.isdigit() and move1 not in lst:
        print('Not that number dipshit!')
        board()
        move()
        break
    elif not move1.isdigit():
        print('Not that number dipshit!')
        board()
        move()
        break

问题是当我尝试运行它时，我不断收到此错误：

<ipython-input-27-8688e8182de8> in move()
      1 def move():
----> 2     conclucion()
      3     move1=(input('Player 1: Type a number!'))
      4     for x in lst:
      5         if move1 == x:

NameError: name 'conclucion' is not defined

有什么想法吗？精简这一点的建议也非常受欢迎。

Answer 1

你拼写了＃34;结论＆＃34;错误，因为＆＃34; conclucion＆＃34;。

名称未定义错误

1 个答案: