Question

我目前正在开设一个大学数学项目，该项目要求我创建一个与抵押相关的应用程序。我正在尝试编写Swift代码来计算每个月抵押贷款的本金和利息。

我编写的代码如下（值得一提的是我对使用Python的一点经验进行编码非常新，这都是自学的，所以任何批评都是受欢迎的！）：

// Declare all variables
// y = periodic interest rate
// n = time left of repayment period (months)

let y = [Float](arrayLiteral: 0.02/12,0.03/12,0.04/12,0.05/12)
let n = [Float](arrayLiteral: 240,180,120,60)

var x = [Float]()
var interest = [Float]()
var T_1 = [Int]()

// Create Array from 0 to 240
for a in 0...240 {
    T_1.append(a)
}

// Create Array of all 240 interest values

for a in 0...239 {
    if a < 60 {
        interest.append(y[0])
        var repay = n[0]
        x.append(repay)
    }
    else if a < 120 {
        interest.append(y[1])
        var repay = n[1]
        x.append(repay)
    }
    else if a < 180 {
        interest.append(y[2])
        var repay = n[2]
        x.append(repay)
    }
    else {
        interest.append(y[3])
        var repay = n[3]
        x.append(repay)
    }
}
print("Interest array:",interest)

// Calculate Each months Principal paid and Interest Paid

func variablerate(P: inout Float) -> [Float] {
    var principal = [Float]()
    var i_paid = [Float]()
    var repayments = [Float]()
    var R = Float(0)
    let temporaryP = P
    i_paid.append(0)

    for a in 0...240 {
        if (a>0) && (a<240) && (interest[a-1] == interest[a]) {
            let ip = P*(1+interest[a-1])-P
            i_paid.append(i_paid[a-1] + ip)
            P = (1+interest[a-1])*temporaryP
            P = P-R
            let h = interest[a]
            R = (P*h)/(1-pow(1+h,Float(interest.count-a)))
            repayments.append(R)
            principal.append(round(100*P)/100)
        }
        else if a==240 || a==241 {
            P = P - R
            principal.append(round(100*P)/100)
            let ip = P*(1+interest[a-1])-P
            i_paid.append(i_paid[a-1] + ip)
            let h = interest[a-1]
            P = P*(1+h)
        }
        else {
            P = P - R
            let h = interest[a]
            R = (P*h)/(1-pow(1+h,Float(interest.count-a)))
            repayments.append(R)
            principal.append(round(100*P)/100)
            let ip = P*(1+interest[a])-P
            i_paid.append(i_paid[a-1] + ip)
            P = P*(1+h)
        }
    }
    return i_paid
    return principal

}
var z = Float(100000)

print(variablerate(P: &z)) //This is where the error appears

给出的错误是：

错误：执行被中断，原因：EXC_BAD_INSTRUCTION（代码= EXC_I386_INVOP，子代码= 0x0）。

对此问题的任何帮助或指导都将受到大力赞赏！

Answer 1

崩溃的原因是索引超出范围。

你正在使Index超出范围异常，因为在代码中你运行的循环从0到240，并且从局部变量 a 减去1，所以在第一次迭代中 a 将包含0并从0减1将给出负指数。

这是错误

for a in 0 ... 240 {
如果（a> 0）＆amp;＆amp; （a＆lt; 240）＆amp;＆amp; （兴趣[a-1] ==兴趣[a]）

以下代码带有更正

// Declare all variables
// y = periodic interest rate
// n = time left of repayment period (months)

let y = [Float](arrayLiteral: 0.02/12,0.03/12,0.04/12,0.05/12)
let n = [Float](arrayLiteral: 240,180,120,60)

var x = [Float]()
var interest = [Float]()
var T_1 = [Int]()

// Create Array from 0 to 240
for a in 0...240 {
    T_1.append(a)
}

// Create Array of all 240 interest values

for a in 0...239 {
    if a < 60 {
        interest.append(y[0])
        var repay = n[0]
        x.append(repay)
    }
    else if a < 120 {
        interest.append(y[1])
        var repay = n[1]
        x.append(repay)
    }
    else if a < 180 {
        interest.append(y[2])
        var repay = n[2]
        x.append(repay)
    }
    else {
        interest.append(y[3])
        var repay = n[3]
        x.append(repay)
    }
}
print("Interest array:",interest)

// Calculate Each months Principal paid and Interest Paid

func variablerate(P: inout Float) -> [Float] {
    var principal = [Float]()
    var i_paid = [Float]()
    var repayments = [Float]()
    var R = Float(0)
    let temporaryP = P
    i_paid.append(0)

    for a in 1...240 { // Code corrected now loop go from 1 to 240 
        if (a>0) && (a<240) && (interest[a-1] == interest[a]) {
            let ip = P*(1+interest[a-1])-P
            i_paid.append(i_paid[a-1] + ip)
            P = (1+interest[a-1])*temporaryP
            P = P-R
            let h = interest[a]
            R = (P*h)/(1-pow(1+h,Float(interest.count-a)))
            repayments.append(R)
            principal.append(round(100*P)/100)
        }
        else if a == 240 || a == 241 {
            P = P - R
            principal.append(round(100*P)/100)
            let ip = P*(1+interest[a-1])-P
            i_paid.append(i_paid[a-1] + ip)
            let h = interest[a-1]
            P = P*(1+h)
        }
        else {
            P = P - R
            let h = interest[a]
            R = (P*h)/(1-pow(1+h,Float(interest.count-a)))
            repayments.append(R)
            principal.append(round(100*P)/100)
            let ip = P*(1+interest[a])-P
            i_paid.append(i_paid[a-1] + ip)
            P = P*(1+h)
        }
    }
    //return i_paid
    return principal

}
var z = Float(100000)

print("\(variablerate(P: &z))")

尝试在Swift Playground中打印函数时出现EXC_BAD_INSTRUCTION错误

1 个答案: