当前文字文件:
NAME S1 2581751 2581758 1
NAME S2 2581761 2581776 1
NAME S3 2581779 2581786 1
NAME S4 2581789 2581804 1
NAME S5 2581807 2581814 1
C A0-ABC
A(1) = 0.1518 !k2
B(2) = 0.4910 !K2O
C(3) = 0.0314 !D2
D(4) = 0.0876 !CO
E(5) = 0.2382 !C1
C CI-ABC
NAME S5 2581779 2581786 1
NAME S5 2581789 2581804 1
NAME S5 2581807 2581814 1
更新的文本文件如下所示:
NAME S1 2581751 2581758 1
NAME S2 2581761 2581776 1
NAME S3 2581779 2581786 1
NAME S4 2581789 2581804 1
NAME S5 2581807 2581814 1
C A0-ABC
A(1) = 0.2145 !k2
B(2) = 0.542 !K2O
C(3) = 0.35 !D2
D(4) = 0.0476 !CO
E(5) = 0.123 !C1
C CI-ABC
NAME S5 2581779 2581786 1
NAME S5 2581789 2581804 1
NAME S5 2581807 2581814 1
我想将文本文件(0.1518
,0.4910
...)中的号码更改为新号码(0.2145
,0.5242
...),其中显示在下面。最初,我取出C A0-ABC
和C CI-ABC
之间的界限并保存在列表中,然后更新数字并将其另存为不同的名称。但我有问题将更新的号码替换为原始文本文件。
import sys
import os
import numpy as np
import math
import string
path='Directory..'
k2 =0.2145
K2O=0.542
D2 = 0.35
CO = 0.476
C1 = 0.123
Update=[str(k2),str(K2O),str(D2),str(CO),str(C1)]
files = os.listdir('.')
f = open(path+'\Input.txt','r')
lines = f.readlines()
copy = False
save_list=[]
for line in lines :
if line.strip() == "C A0-ABC":
copy = True
elif line.strip() == "C CI-ABC":
copy = False
elif copy:
save_list.append(line)
file= open(path+'\Update_INPF.txt','w')
lis=[x.split() for x in save_list]
A = [str(x[0]) for x in lis]
B = [str(x[1]) for x in lis]
C = Update
D= [str(x[3]) for x in lis]
F=zip(A,B,C,D)
for x in list(F):
file.write("{0}\t{1}\t{2}\t{3}\n".format(*x))
file.close()
print save_list
答案 0 :(得分:0)
path = 'Directory..'
k2 = 0.2145
K2O = 0.542
D2 = 0.35
CO = 0.476
C1 = 0.123
fold = open(path + '\Input.txt','r')
fnew = open(path + '\Update_INPF.txt','w')
for line in f.readlines():
line = line.split()
if line[0] == 'A(1)':
newline = ' '.join(line[:2] + [str[k2]] + line[-1])
elif line[0] == 'B(2)':
newline = ' '.join(line[:2] + [str[K20]] + line[-1])
elif line[0] == 'C(3)':
newline = ' '.join(line[:2] + [str[D2]] + line[-1])
elif line[0] == 'D(4)':
newline = ' '.join(line[:2] + [str[C0]] + line[-1])
elif line[0] == 'E(5)':
newline = ' '.join(line[:2] + [str[C1]] + line[-1])
else:
newline = line
fnew.write(newline)
fold.close()
fnew.close()