Qtsql中的参数计数不匹配

时间:2016-11-16 16:08:48

标签: c++ qt qtsql

我试图将数据插入QtSql数据库,但我一直收到错误:

"Parameter count mismatch"

我可能做错了什么?

#include <QtSql>

int main(int argc, char *argv[])
{
    QCoreApplication a(argc, argv);

    qDebug() << QSqlDatabase::drivers();

    QSqlDatabase db = QSqlDatabase::addDatabase("QSQLITE");
    db.setHostName("LOCALHOST");
    db.setDatabaseName("people");
    db.setUserName("root");
    db.setPassword("");

    if(db.open()) {
        qDebug() << "Opened!";

        QSqlQuery query;

        query.prepare("INSERT INTO person (id, forename, surname) "
                      "VALUES (:id, :forename, :surname)");
        query.bindValue(":id", 1001);
        query.bindValue(":forename", "Bart");
        query.bindValue(":surname", "Simpson");
        query.exec();

        if( !query.exec() )
            qDebug() << query.lastError().text();
        else
            qDebug( "Inserted!" );

        db.close();

    } else {
        qDebug() << "Not opened";
    }
}

1 个答案:

答案 0 :(得分:2)

您在数据库中没有名为person的表。您正在尝试将值插入到不存在的表中。

我认为错误信息是错误的。但无论如何,我在代码中添加了CREATE语句,以便在执行INSERT语句之前创建表:

#include <QtSql>

int main(int argc, char *argv[])
{
    QCoreApplication a(argc, argv);

    QSqlDatabase db = QSqlDatabase::addDatabase("QSQLITE");
    db.setDatabaseName(":memory:");

    if(!db.open()){
        qDebug() << "Not opened";
        return 1;
    }
    qDebug() << "Opened!";

    QSqlQuery query;

    //CREATE the table before executing the INSERT statement
    query.exec("CREATE TABLE person (id INTEGER, forename TEXT, surname TEXT);");

    query.prepare("INSERT INTO person (id, forename, surname) "
                  "VALUES (:id, :forename, :surname)");
    query.bindValue(":id", 1001);
    query.bindValue(":forename", "Bart");
    query.bindValue(":surname", "Simpson");

    if( !query.exec() )
        qDebug() << query.lastError().text();
    else
        qDebug( "Inserted!" );

    return 0;
}

现在打印Inserted!。但是如果我注释掉CREATE语句行,我会在你的问题中得到同样的错误:

" Parameter count mismatch"