Question

我是一个python noob，在学校我需要编写一个有6个选项的程序：

查找平方根
平均考试成绩
显示税款
随机性
查找日期和今天的天数
并退出

除日期外，我完成了所有这些工作。这是我的代码：

   #test.py
    from math import *
    from random import *
    from datetime import *
    cont = True
    a = 0
    print("My Custom Functions")
    print("1. What's the root?")
    print("2. Average my test scores.")
    print("3. Show me the tax.")
    print("4. Randomness.")
    print("5. How many days?")
    print("6. Exit")

    def option():
     cont = True
     global a
     global cont
     o = input("Enter an option")
     if o == "1":
        a = float(input("This function prints a square root. Enter a number (1-9999):"))
        print(sqrt(a))
    if o == "2":
        b = input("Enter any number of test scores (1-100). Separate each by a space:")
        l = []
    l = [float(score) for score in b.split()]
    avg =sum(l) / len(l)
    print(round(avg,5))
    if o == "3":
        c = float(input("This function shows how much your sales tax (7.5%) is for your purchase. Enter the purchase amount (<10,000):"))
        d = c * .075
        print("$",c+d)
    if o == "4":
     print(randrange(1,100))
    if o == "5":
        d = input("“This function shows how many days there are between today and a date you enter. Enter a date in this format (mm dd yy):")
        int(d)
        d1 = date(d)
        d2 = date.today()
        print(d2 - d1)
    if o == "6":
        print("Exitting Program")
        cont = False

    while cont == True:
    option()

我编辑了代码作为我收到的答案。我现在得到ValueError：int（）的无效文字，基数为10：'10 24 18'。我已经研究过一个没有运气的解决方案。

Answer 1

对于选项2，在分割字符串后转换为float 。

b = input("Enter any number of test scores (1-100). Separate each by a space:") l = [float(score) for score in b.split()] print(sum(l) / len(l))

对于选项5，您需要正确使用datetime.date个对象。

d = input("“This function shows how many days there are between today and a date you enter. Enter a date in this format (mm dd yy):") mm, dd, yy = [int(t) for t in d.split()] d1 = date(2000 + yy, mm, dd) print((date.today() - d1).days)

Answer 2

空格分隔float的列表不是float，您需要先将其拆分，然后将它们转换为浮点数：

if o == "2":
    b = input("Enter any number of test scores (1-100). Separate each by a space:")
    l = list(map(float, b.split()))  # or use a list comprehension
    print(sum(l) / len(l))

而且您无法将日期转换为int，这是没有意义的。

学校计划无效

2 个答案: