Question

我使用Refit for RestAPI。我需要创建相同api/item?c[]=14&c[]=74

的查询字符串

在改装界面中我创建了方法

[Get("/item")]
Task<TendersResponse> GetTenders([AliasAs("c")]List<string> categories=null);

创建CustomParameterFormatter

string query = string.Join("&c[]=", values);

CustomParameterFormatter生成字符串14&c[]=74

但改装编码参数和生成的网址api/item?c%5B%5D=14%26c%5B%5D%3D74

如何禁用此功能？

Answer 1

首先是你的api服务器能够解析以下内容吗？ api/item?c%5B%5D=14%26c%5B%5D%3D74

编码非常适合避免代码注入服务器。

这是改装有点自以为是，即uris应编码，服务器应升级为读取编码的uris。

但这显然应该是改装中的选择设置，但事实并非如此。

所以你现在可以通过使用DelegatingHandler来做到这一点：

/// <summary>
/// Makes sure the query string of an <see cref="System.Uri"/>
/// </summary>
public class UriQueryUnescapingHandler : DelegatingHandler
{   
    public UriQueryUnescapingHandler()
        : base(new HttpClientHandler()) { }
    public UriQueryUnescapingHandler(HttpMessageHandler innerHandler)
        : base(innerHandler)
    { }

    protected override Task<HttpResponseMessage> SendAsync(HttpRequestMessage request, CancellationToken cancellationToken)
    {
        var uri = request.RequestUri;
        //You could also simply unescape the whole uri.OriginalString
        //but i don´t recommend that, i.e only fix what´s broken
        var unescapedQuery = Uri.UnescapeDataString(uri.Query);

        var userInfo = string.IsNullOrWhiteSpace(uri.UserInfo) ? "" : $"{uri.UserInfo}@";
        var scheme = string.IsNullOrWhiteSpace(uri.Scheme) ? "" : $"{uri.Scheme}://";

        request.RequestUri = new Uri($"{scheme}{userInfo}{uri.Authority}{uri.AbsolutePath}{unescapedQuery}{uri.Fragment}");
        return base.SendAsync(request, cancellationToken);
    }
}


Refit.RestService.For<IYourService>(new HttpClient(new UriQueryUnescapingHandler()))

如何在Refit中禁用urlencoding get-params？

1 个答案: