Question

对于解析json我使用JSONArray和JsonObject：

 protected void parseJson()
    {
        JSONObject object=null;
        try {

            object=new JSONObject(json);
            myArray=object.getJSONArray(MY_ARRAY);
            Log.e("Array Length",""+myArray.length());
            key_id=new String[myArray.length()];
            key_name=new String[myArray.length()];

            for (int i=0;i<=myArray.length();i++)
            {
                JSONObject fetchObject=myArray.getJSONObject(i);

                    key_id[i] = fetchObject.getString(KEY_ID);
                    key_name[i] = fetchObject.getString(KEY_NAME);


            }
        } catch (JSONException e) {
            e.printStackTrace();
        }
    }

JSON DATA：

 {
        "data": [{
            "key": 1,
            "myval": "hello"
        }, {
            "key": 1,
            "myval": "hello"
        }, {
            "key": 1,
            "myval": "hello"
        }, null, {
            "key": 1,
            "myval": "hello"
        }, {
            "key": 1,
            "myval": "hello"
        }]
    }

我的问题是，当fetchObject获取null对象时，它给我org.json.JSONObject$1无法在try catch中转换为JSONObject。请帮帮我怎样才能解决这个问题.....感谢阅读......

Answer 1

if(obj.length() == 0)

就是我要做的。

JSONObject fetchObject;

if(flowerArray.getJSONObject(i).length() !=0)

/

fetchObject = flowerArray.getJSONObject(i)
    if(fetchObject== null)

Answer 2

在阅读JsonArray和JsonObject doc之后，我明白了如何解决这个问题。

protected void parseJson()
    {
        JSONObject object=null;
        try {

            object=new JSONObject(json);
            myArray=object.getJSONArray(MY_ARRAY);
            Log.e("Array Length",""+myArray.length());
            key_id=new String[myArray.length()];
            key_name=new String[myArray.length()];

            for (int i=0;i<=myArray.length();i++)
            {

                JSONObject fetchObject=myArray.optJSONObject(i);

                    if(fetchObject==null)
                   {
                     //do nothing
                   }
                   else
                   {
                    key_id[i] = fetchObject.getString(KEY_ID);
                    key_name[i] = fetchObject.getString(KEY_NAME);

                   }
            }
        } catch (JSONException e) {
            e.printStackTrace();
        }
    }

解析json字符串时，org.json.JSONObject $ 1无法转换为JSONObject错误

2 个答案: