Question

在这种情况下如何打印键值对：

a = [
{"name": "Tom", "age": 10},
{"name": "Mark", "age": 5},
{"name": "Pam", "age": 7}
]

search_name = 'Tom'

for i in a:
   for key in i:
      if (i[key] == search_name):
           print (item for item in a).next()
      else:
           print 'No Name'

我不想看到'没有名字'的消息

Answer 1

实现它的更简洁方法是：

for dic in a:
    name = dic.get('name')  # will return None if dic has no `name` key
    if name and name == search_name:
        print dic
    else:
        print 'No Name'

但无论如何，如果不想看No Name，那么就不要打印它。

Answer 2

当然你看到了。您迭代字典键（for key in i），当您尝试将i["age"]与search_name匹配时，它会显示No Name。

Answer 3

试

for dict in a:
    if search_name in dict.values():
        print dict
    else:
        print "No name"

在python中打印字典的键值对

3 个答案: