Question

在我的程序中，我有一个sqlite数据库，其中数据通过tkinter gui中的条目小部件附加到。我喜欢它，所以数据在验证后才会附加到数据库，因为目前没有验证。

例如，在我的下面的函数中，它将customerID，forename，surname，address和phone number附加到我数据库中的customer表中。我想这样，所以customerID条目只接受整数，forename，surname和address为NOT NULL，phoneNumberEntry只接受整数。

我见过人们使用validate命令但我不认为我能够实现它，因为我已经使用命令将数据附加到数据库。

def appendToCustomerTableEntry(event):
    top = Toplevel()
    top.title("Add to customer table")

    Label(top, text = "customerID: ").grid(sticky = E)

    customerIDEntry = Entry(top)
    customerIDEntry.grid(row = 0, column = 1)

    Label(top, text = "Forename: ").grid(row = 1, sticky = E)

    customerForenameEntry = Entry(top)
    customerForenameEntry.grid(row = 1, column = 1)

    Label(top, text = "Surname: ").grid(row = 2, sticky = E)

    customerSurnameEntry = Entry(top)
    customerSurnameEntry.grid(row = 2, column = 1)

    Label(top, text = "Address: ").grid(row = 3, sticky = E)

    customerAddressEntry = Entry(top)
    customerAddressEntry.grid(row = 3, column = 1)

    Label(top, text = "Phone Number: ").grid(row = 4, sticky = E)

    customerPhoneNumberEntry = Entry(top)
    customerPhoneNumberEntry.grid(row = 4, column = 1)

    exitButton = Button(top, text = "Exit", command = top.destroy)
    exitButton.grid(row = 5, column = 2, sticky = W)

    appendButton = Button(top, text = "Append", command =   lambda:appendToCustomerTable
                  (customerIDEntry.get(), customerForenameEntry.get(), customerSurnameEntry.get(),
                   customerAddressEntry.get(), customerPhoneNumberEntry.get()))
    appendButton.grid(row = 5, column = 1, sticky = E)


def appendToCustomerTable(customerID, Forename, Surname, Address, TelephoneNumber):
    c.execute("INSERT INTO customerTable VALUES (?, ?, ?, ?, ?);", (customerID, Forename, Surname, Address, TelephoneNumber ))
    conn.commit()

Answer 1

这是一个sql卫生问题，还是python编程问题？

如果sql卫生，你需要弄清楚要拒绝的sql字符串或字符，也可能有库这样做。 https://www.owasp.org/index.php/SQL_Injection_Prevention_Cheat_Sheet

以编程方式运行if语句，改变操作顺序并使用字符串替换。 http://bobby-tables.com/python.html

在您的代码中，您需要注意的是有人试图通过您的字段发布代码。仔细看看最后一个链接。

Answer 2

第一次尝试＆＃34; dont repeat your self＆＃34;

# you can declare here the input type of your argument default and the type of them 
def build(ui_title = [], int_arg = 0):
    # on top you can also assert the input
    # continue only if ui_title is True else give a AssertionError 
    assert (ui_title), "list is empty!!!"

    # lets check int_arg for int
    assert (int_arg==int), "{0} except int get {1}".format(int_arg ,type(int_arg))

    for row,text in enumerate(ui_title):
        Label(top, text = str(text)).grid(sticky = E)
        customerIDEntry = Entry(top)
        customerIDEntry.grid(row = int(row), column = 1)
        if text=="Exit":
            exitButton = Button(top, text = str(text), command = top.destroy)
            exitButton.grid(row = int(row), column = 2, sticky = W)

ui_title = ["customerID", "Forename: ", "Surname: ", "Address: ", "Phone Number: ", "Exit"]
build(ui_title) # will work
build(ui_title, int_arg = "Hallo") # will not work, because int_arg get string and the build method will raise a AssertionError

Python - 如何验证tkinter输入字段

2 个答案: