我在Angular2应用程序中有以下类
export class Contact {
constructor(
public has_reply: boolean,
public archived: boolean
) { }
getStatus() : string {
if (this.archived) {
return "Archived";
}
if (this.has_reply) {
return "Answered";
}
return "Waiting";
}
}
由服务
返回@Injectable()
export class ContactsService {
private contactsData : BehaviorSubject<Array<Contact>> = null;
constructor(private http: Http) {
this.contactsData = new BehaviorSubject<Array<Contact>>([]);
}
/**
* get the list of contacts
*/
populateContacts() : Array<Contact> {
return this.http.get('/api/contacts/').map(
(res: Response) => {return res.json()}
).subscribe(
jsonData => {
this.contactsData.next(<Array<Contact>> jsonData);
}
);
}
onContactsChanged() : Observable<Array<Contact>>{
return this.contactsData.asObservable();
}
}
用于组件
@Component({
selector: 'app-home',
templateUrl: './home.component.html',
styleUrls: ['./home.component.css']
})
export class HomeComponent implements OnInit {
private contacts: Array<Contact> = [];
constructor(
private contactsApi : ContactsService
) { }
ngOnInit() {
this.contactsApi.onContactsChanged().subscribe(
(contacts: Array<Contact>) => {this.contacts = contacts;}
);
this.contactsApi.populateContacts();
}
}
并显示在模板中
<table class="table table-striped table-bordered">
<tr *ngFor="let contact of contacts">
<td>
{{ contact.getStatus() }}
</td>
</tr>
我收到以下错误
EXCEPTION: Error in ./HomeComponent class HomeComponent - inline
template:11:8 caused by: self.context.$implicit.getStatus is not a function
我的做法有什么问题? Angular2是否允许调用这样的类方法?
注意:Calling method from a Angular 2 class inside template看起来类似问题,但没有帮助
答案 0 :(得分:1)
根据@AdnanA的建议,问题是一个投射问题。见How to do runtime type casting in TypeScript?
我通过强制转换数组的每个对象来修复:请参阅https://stackoverflow.com/a/32186367/117092
// Thank you! https://stackoverflow.com/a/32186367/117092
function cast<T>(obj, cl): T {
obj.__proto__ = cl.prototype;
return obj;
}
@Injectable()
export class ContactsService {
private contactsData : BehaviorSubject<Array<Contact>> = null;
constructor(private http: Http) {
this.contactsData = new BehaviorSubject<Array<Contact>>([]);
}
/**
* get the list of contacts
*/
populateContacts() : Array<Contact> {
return this.http.get('/api/contacts/').map(
(res: Response) => {return res.json()}
).subscribe(
jsonData => {
// WRONG! this.contactsData.next(<Array<Contact>> jsonData);
// FIXED BY
let contactsArray: Array<Contact> = [];
for (let i=0, l=jsonData.length; i<l; i++) {
let contact = cast<Contact>(jsonData[i], Contact);
contactsArray.push(contact);
}
this.contactsData.next(contactsArray);
}
);
}
onContactsChanged() : Observable<Array<Contact>>{
return this.contactsData.asObservable();
}
}
答案 1 :(得分:0)
如果数据是异步获取的,则需要防范null
{{ contact?.getStatus() }}