Question

我需要在表格中显示json数据，并且我使用http.get函数来检索json数据，但我无法显示它们。

我试过这个但没有工作：

HTML ：

<html>
    <head>
        <script src="http://ajax.googleapis.com/ajax/libs/angularjs/1.2.26/angular.min.js" />
        <script>
            myApp = angular.module('myApp', [])
            myApp.controller('myController', function($scope, $http){
                $http.get('data.json').success(function(response){
                    $scope.myData = response;
                });
                $scope.removeName = function(row) {
                    $scope.myData.splice($scope.myData.indexOf(row),1)
                }
            });
        </script>
    </head>
    <body ng-app="myApp" ng-controller="myController">
        Search: <input type="text" value="" ng-model="search" /><br><br>
        <table border=1>
            <tr ng-repeat = "Data in myData | filter : search">
                <td>{{myData.name}}</td>
                <td>{{myData.company}}</td>
                <td><a href="" ng-click="removeName(data)">Remove</a></td>
            </tr>
        </table>
    </body>
</html>

JSON ：

[
 {"name":"Steve Jobs", "company":"Apple"},
 {"name":"Larry Page", "company":"Google"},
 {"name":"Bill Gates", "company":"Microsoft"},
 {"name":"Larry Ellison", "company":"Oracle"},
 {"name":"Sergey Brin", "company":"Google"},
 {"name":"Steve Wozniak", "company":"Apple"}

]

CONSOLE ERROR ：

Uncaught Error: [$injector:modulerr] http://errors.angularjs.org/1.5.8/$injector/modulerr?p0=myApp&p1=Error%3A%2…ogleapis.com%2Fajax%2Flibs%2Fangularjs%2F1.5.8%2Fangular.min.js%3A21%3A179)
    at https://ajax.googleapis.com/ajax/libs/angularjs/1.5.8/angular.min.js:6:412
    at https://ajax.googleapis.com/ajax/libs/angularjs/1.5.8/angular.min.js:40:222
    at q (https://ajax.googleapis.com/ajax/libs/angularjs/1.5.8/angular.min.js:7:355)
    at g (https://ajax.googleapis.com/ajax/libs/angularjs/1.5.8/angular.min.js:39:319)
    at cb (https://ajax.googleapis.com/ajax/libs/angularjs/1.5.8/angular.min.js:43:336)
    at c (https://ajax.googleapis.com/ajax/libs/angularjs/1.5.8/angular.min.js:20:390)
    at Bc (https://ajax.googleapis.com/ajax/libs/angularjs/1.5.8/angular.min.js:21:179)
    at fe (https://ajax.googleapis.com/ajax/libs/angularjs/1.5.8/angular.min.js:20:1)
    at https://ajax.googleapis.com/ajax/libs/angularjs/1.5.8/angular.min.js:317:386
    at HTMLDocument.b (https://ajax.googleapis.com/ajax/libs/angularjs/1.5.8/angular.min.js:189:487)

有人可以帮我解决这个错误吗？感谢＆＃39; S

Answer 1

哟，你正在重复myData到Data属性，但是你正在输出myData：）

<tr ng-repeat = "Data in myData | filter : search">
            <td>{{Data.name}}</td>
            <td>{{Data.company}}</td>
            <td><a href="" ng-click="removeName(Data)">Remove</a></td>
        </tr>

试试这个，请注意我在{{}}

中所做的更改

好的，这是正常工作的代码 - https://plnkr.co/edit/dLei9iIM9ddfBAjoAytZ我刚刚用1.5.6替换你的角度及其工作。

angularjs没有用http.get显示json数据

1 个答案: