Question

我的Json文件有以下类：

using System.Collections.Generic;

namespace MITSonWald
{
    public class ExtLine
    {
        public List<Dictionary<string, List<LineList>>> LineList { get; set; }
    }

    public class LineList
    {
        public List<Dictionary<string, List<Device>>> DeviceList { get; set; }
    }

    public class Device
    {
        public string Volume { get; set; }
        public string Name { get; set; }
    }
}

生成的Json文件

{
  "LineList":[
    {
      "TapiLine22":[
        {
          "DeviceList":[
            {
              "192.168.10.204":[
                {
                  "Volume":"5",
                  "Name":"Büro"
                }
              ]
            }
          ]
        }
      ]
    }
  ]
}

我想在DeviceList添加一个对象，但我无法完成。

我尝试了什么

/* Deserialize Json File */
dynamic json =
    JsonConvert.DeserializeObject<ExtLine>(
           File.ReadAllText(AppDomain.CurrentDomain.BaseDirectory + "cfg\\lines.json"));

List<Dictionary<string, List<Device>>> myDevice = new List<Dictionary<string, List<Device>>>
{
    new Dictionary<string, List<Device>>
    {
        {
            "192.168.10.205",
            new List<Device>
            {
                new Device
                {
                    Name = "Zimmer2",
                    Volume = "5"
                }
            }
        }
    }
};

json.LineList[0]["TapiLine22"][0].DeviceList.Add(myDevice);

抛出异常（Google翻译自德语）

Additional Information: The best match for the overloaded System.Collections.Generic.List <System.Collections.Generic.Dictionary <string, System.Collections.Generic.List <MITSonWald.Device >>>. Add (System.Collections.Generic. Dictionary <string, System.Collections.Generic.List <MITSonWald.Device >>) method contains some invalid arguments.

Answer 1

从例外情况看，你的Add似乎是：

Add (Dictionary<string, List<MITSonWald.Device>>)

但您要添加

类型的对象

List<Dictionary<string, List<Device>>>

这应该有效（但它会取代你的清单）：

json.LineList[0]["TapiLine22"][0].DeviceList = myDevice;

因为你的myDevice与DeviceList的类型相同。

您也可以创建字典并将其添加到DeviceList（只需抛出不需要的列表）：

var myDevice = new Dictionary<string, List<Device>>
{
    {
        "192.168.10.205",
        new List<Device>
        {
            new Device
            {
                Name = "Zimmer2",
                Volume = "5"
            }
        }
    }
}

用json.net更新json对象

1 个答案: