Question

到目前为止，我已经查看了大约15次但无济于事。我不明白为什么这是断层错误？它甚至没有得到“印刷”声明，这是没有意义的。错误代码实际上工作（当我没有共享内存时）我有一个load.c程序，但它完美的工作（我100％肯定这一点）

#include <stdio.h>
#include <stdlib.h>
#include <sys/ipc.h>
#include <sys/types.h>
#include <sys/sem.h>
#include "header.h"

//BEGIN MAIN FUNCTION
main()
{
    int id;             //ID to data shmem
    struct StudentInfo *infoptr;    //ptr to data
    int found = 0;          //found 'boolean'
    char input[15];         //user input buffer
    struct StudentInfo *beginptr;   //ptr to beginning of data
    int rcid;           //Read count ID to shmem
    int *rcptr;         //RC ptr
    int sema_set;           //ID to shared semaphores

    //Find the shmem at our ID
        id = shmget(KEY,SEGSIZE,0);
        if(id < 0)
        {
                perror("Query: shmget failed");
                exit(1);
        }

    //set the ptr to our shared mem and attach to program
        infoptr = (struct StudentInfo *)shmat(id,0,0);
        if(infoptr <= (struct StudentInfo *)(0))
        {
                perror("Query: shmat failed");
                exit(1);
        }

    //Get our RC in shared memory 
    rcid = shmget(RCKEY,READCOUNT,0);
    if(rcid < 0)
    {
        perror("Query: shmget failed");
        exit(1);
    }
    //Set ptr to shmem and attach to process
    rcptr = (int*)shmat(rcid,0,0);
    if(rcptr <= (int*)(0))
    {
        perror("Print: Shmat failed");
        exit(1);
    }

    //Get semaphores
    sema_set = semget(SEMA_KEY,NUM_SEMAPHS,0);
    if(sema_set < 0)
    {
        perror("Query: Semget failed");
        exit(1);
    }   

    //Set program to queue up to wait
    Wait(sema_set,1);

    //Increment the read counter
    *rcptr += 1;

    //If we are the first reader, stop writers
    if(*rcptr == 1)
    Wait(sema_set,0);

    //Signal readers
    Signal(sema_set,1);

    //Set our begin ptr
    beginptr = infoptr;

    //Begin user input loop
    while(1)
    {
    //Ask user for input IT DOESN"T EVEN GET TO HERE <--
    printf("Please input a student ID :");
    scanf("%s",input);

    //While the record is not found search  
    while(strcmp(infoptr->Name,"")!=0 && found != 1)
    {
        //If record found, print the record
        if((strncmp(input,infoptr->ID,9)) == 0)
        {
            //Set found
            found = 1;

            printf("\n%s\n",infoptr->Name);
                    printf("%s\n",infoptr->telNumber);
                    printf("%s\n",infoptr->Address);
                    printf("%s\n\n",infoptr->ID);
        }
        else
            infoptr++;
    }

    //If not found, print error message
    if(found == 0)
        printf("Record not found.\n");

    //Wait on readers
    Wait(sema_set,1);
    //Decrement
    *rcptr--;
    //If no readers left
    if(*rcptr == 0)
        Signal(sema_set,0); //Signal writers
    //Signal readers
    Signal(sema_set,1);
    exit(0);        
    }
}

HEADER

#define KEY  ((key_t)(11111)) /*change it to last five digits of your SSN*/
#define SEGSIZE  sizeof(struct StudentInfo)

#define NUM_SEMAPHS 2
#define SEMA_KEY   ((key_t)(1111)) /* change this to last four digits of SSN */

#define READCOUNT sizeof(int)   //Set the size of shmem for read count
#define RCKEY ((key_t)(4003))   //Set the key of the shmem for RCount

//Struct student info
struct StudentInfo{
  char Name[20];
  char ID[15];
  char Address[50];
  char telNumber[15];
};

//Checks the semaphore whether or not to wait
void Wait(int semaph, int n);
//Signals that it's ok to run
void Signal(int semaph, int n);
//Gets the semaphore information
int GetSemaphs(key_t k, int n);

Answer 1

您的问题可能来自您使用shmat。在C中，永远不要转换这种函数的返回类型。您觉得需要它可能意味着您有一个虚假的错误消息来自您缺少“sys / shm.h”标头的事实。

在这种情况下会发生的事情是gcc采用int的返回类型，通常是32位数量，并将其重新解释为指针。因此shmat给你的地址的上半部分丢失了。

作为一般规则，不要抛弃问题。如果所有标题都已正确写入，则很少需要在C中进行强制转换。转换系统函数的返回类型几乎总是错误的。

Answer 2

Valigrind和GDB是你的朋友

请提供完整的代码，以便我们编译并帮助您。盯着源代码并不是一种神奇的调试方法：）

确保使用编译器上的调试选项（-g etc）进行编译。

否则，结账valgrind的memcheck。如果有已编译的程序，请运行：

valgrind ./myprogram

您可能会得到类似于以下内容的输出：

==584== Use of uninitialised value of size 8
==584==    at 0x400480: segfaultme (p.c:6)
==584==    by 0x40049B: main (p.c:13)
==584== 
==584== Invalid write of size 4
==584==    at 0x400480: segfaultme (p.c:6)
==584==    by 0x40049B: main (p.c:13)
==584==  Address 0x0 is not stack'd, malloc'd or (recently) free'd
==584== 
==584== 
==584== Process terminating with default action of signal 11 (SIGSEGV)
==584==  Access not within mapped region at address 0x0
==584==    at 0x400480: segfaultme (p.c:6)
==584==    by 0x40049B: main (p.c:13)
==584==  If you believe this happened as a result of a stack
==584==  overflow in your program's main thread (unlikely but
==584==  possible), you can try to increase the size of the
==584==  main thread stack using the --main-stacksize= flag.
==584==  The main thread stack size used in this run was 10485760.

使用以下方法破解GDB：

gdb ./myprog然后输入 r return

您将获得有关segfault发生位置的更多信息：

(gdb) r
Starting program: /home/aiden/tmp/a.out 

Program received signal SIGSEGV, Segmentation fault.
0x0000000000400480 in segfaultme (p=0x0) at p.c:6
6       *p = 22;
Missing separate debuginfos, use: debuginfo-install glibc-2.11.2-1.x86_64
(gdb) bt
#0  0x0000000000400480 in segfaultme (p=0x0) at p.c:6
#1  0x000000000040049c in main () at p.c:13

输入 b t return 也会给你一个回溯。在上面的示例中，我们可以看到p.c中segfaultme()的第6行，其中我解除引用p是问题所在，它显示segfaultme()被main()调用

希望这有帮助！请记住尽可能多地接触可以帮助您的工具！

段故障？你能找到吗？因为我不能

2 个答案: