Question

所以我只是看到我是否可以建立一个死的简单聊天应用程序，我面临一个问题...我的电脑上运行的服务器和手机上的客户端，一旦客户端连接到我的电脑我然后可以去我的电脑，写我想要的消息，他们将出现在我的手机（客户端），但当我尝试从我的手机发送消息时，它只会发送一条消息，然后不再有任何想法？

服务器

static OutputStream out;
static InputStream in;
String name = "Server";

public static void main(String args[]){
    System.out.println("Server On");

    //Server
    new Thread(new Runnable(){
        @Override
        public void run(){
            new Main().start();
        }}).start();
    //Scanner for text input
    new Main().scrnn();
}

public void scrnn(){
    Scanner lol = new Scanner(System.in);
    if(lol.hasNext()){
        try {
            out.write((name + ": " +lol.nextLine().toString()).getBytes());
            out.flush();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
    scrnn();
}

public void start(){
    try{
        ServerSocket sok = new ServerSocket(42069);
        while(true){
            Socket sk = sok.accept();
            in = sk.getInputStream();
            out = sk.getOutputStream();
            byte[] buffer = new byte[1024];
            in.read(buffer);
            String recievedData = new String(buffer);
            System.out.println(recievedData);
            out.write(recievedData.getBytes());
        }
    }catch(Exception e){
        e.printStackTrace();
    }
}

和客户端:(安卓手机）

OutputStream out;
InputStream in;
Socket sk;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    list = new Object[]{"Thanks for using Monsterchat"};

    Button button = (Button)findViewById(R.id.buttonSend);
    listView = (ListView) findViewById(R.id.listView);

    new Thread(new Runnable() {
        @Override
        public void run() {
            try {
                sk = new Socket("10.0.0.9", 42069);
                sk.setKeepAlive(true);

                out = sk.getOutputStream();
                in = sk.getInputStream();

                //This will send fine but if you look at the button onclick it wont send that :(
                out.write((name + " Joined the group!").getBytes());

                //This is how i can send constant messages from the server though
                listenForData();
            }catch(Exception e){
                e.printStackTrace();
            }
        }
    }).start();

    button.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            new Thread(new Runnable() {
                @Override
                public void run() {
                    try {
                        out.write("succ".getBytes());
                    } catch (Exception e) {
                        e.printStackTrace();
                    }
                }
            }).start();
        }
    });
}

    public void listenForData() throws Exception{
    byte[] buffer = new byte[1024];
    in.read(buffer);
    final String recievedData = new String(buffer);
    runOnUiThread(new Runnable() {
        @Override
        public void run() {
            //Update listView with new message
            buildList(recievedData);
        }
    });
    //Repeat
    listenForData();
}

很抱歉这里有很多代码，而且看起来不对的logcat也没有输出

Answer 1

    while(true){
        Socket sk = sok.accept();
        in = sk.getInputStream();
        out = sk.getOutputStream();
    Dr    byte[] buffer = new byte[1024];
        in.read(buffer);
        String recievedData = new String(buffer);
        System.out.println(recievedData);
        out.write(recievedData.getBytes());

那个循环是错误的。收到一条消息后，服务器将丢弃sk并等待新客户端。

你最好试试;

        Socket sk = sok.accept();
        in = sk.getInputStream();
        out = sk.getOutputStream();
        byte[] buffer = new byte[1024];
    while(true){
        int nread = in.read(buffer);
        String recievedData = new String(buffer, 0, nread);
        System.out.println(recievedData);
        out.write(recievedData.getBytes());

Android SDK，从客户端到服务器的输出流不起作用

1 个答案: