我有两个相关模型(为清晰起见缩写)
const model = (sequelize, DataTypes) => {
const User = sequelize.define('User', {
fullName: {
type: DataTypes.STRING,
allowNull: false,
validate: {
notEmpty: true,
len: [1,255]
}
}
},
{
classMethods: {
associate: function(models) {
User.hasMany(models.Meeting, {as: 'chairedMeetings', foreignKey: 'chairmanId'})
}
}
}
)
return User
}
和
const model = (sequelize, DataTypes) => {
const Meeting = sequelize.define('Meeting', {
title: {
type: DataTypes.STRING,
allowNull: false,
validate: {
notEmpty: true,
len: [1,255]
}
}
}, {
classMethods: {
associate: function(models) {
Meeting.belongsTo(models.User, {as: 'chairman'})
}
}
}
)
return Meeting
}
module.exports = model
我为之前创建的id = 1
用户创建了一个新会议,如下所示:
const data = {
title: 'Some amazing meeting title',
chairmanId: 1
}
Meeting.create(data, {include: [{all: true, nested: true}]}).then(meeting => {
const chairmanId = meeting.get('chairmanId') // ===> this is 1 as expected
const chairman = meeting.get('chairman') // ===> but this is undefined
}
如何获取sequelize以返回相关记录,而无需手动完成关联,并findOne
id
对其进行检查?
答案 0 :(得分:1)
好的想通了:
解决方案是在创建后执行reload
。
Meeting.create(data, {include: [{all: true, nested: true}]}).then(meeting => {
const chairmanId = meeting.get('chairmanId') // ===> this is 1 as expected
meeting.reload({include: [{all: true, nested: true}]}).then(reloadedMeeting => {
const chairman = reloadedMeeting.get('chairman') // ===> is a user!
})
}
我想sequelize不会在创建后自动重新加载,以防你真正关心刚创建的模型,而你只是想知道它已经保存了。