使用Blueprints将参数传递给Flask应用程序

Question

我已经查看了一些示例和教程，据我所知，我有正确的观点。通过下面的基本示例，我收到以下错误：TypeError: view() got an unexpected keyword argument 'id'

from flask import Blueprint, jsonify

location_app = Blueprint('location_app', __name__)

@location_app.route('/location/', defaults={'id': '0'})
@location_app.route('/location/<id>', methods=['GET'])
def view():
    return "location view"

Answer 1

您的函数必须采用url定义的变量。像这样：

@location_app.route('/location/<id>', methods=['GET'])
def view(id):
    return "location view"