更正存在多个WHERE的多个COLUM的SUM的MySQL语法？

Question

我有以下数据库表：

+----------------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +----------------+-------------+------+-----+---------+----------------+ | results_id | int(11) | NO | PRI | NULL | auto_increment | | community_id | int(11) | NO | | NULL | | | player1_id | int(11) | NO | | NULL | | | player1_name | varchar(50) | NO | | NULL | | | player1_team | varchar(50) | NO | | NULL | | | player1_goals | int(11) | NO | | NULL | | | player1_result | varchar(3) | NO | | NULL | | | player2_goals | int(11) | NO | | NULL | | | player2_result | varchar(3) | NO | | NULL | | | player2_id | int(11) | NO | | NULL | | | player2_name | varchar(50) | NO | | NULL | | | player2_team | varchar(50) | NO | | NULL | | | player1_pts | int(11) | NO | | NULL | | | player2_pts | int(11) | NO | | NULL | | | date | date | NO | | NULL | | +----------------+-------------+------+-----+---------+----------------+

我想运行一个MySQL查询，告诉我一名球员的进球数最多。

该玩家可以是player1或player2。

我想它是这样的：

select member, goals, count(*) Total
from 
(
select player2_name as member, player1_goals as goals
from results
WHERE player1_id = 2
union all
select player1_name as member, player2_goals as goals
from results
WHERE player2_id = 2 

) AS T

group by goals
order by Total desc
Limit 1

这给出了一个结果：

member        | goals | Total
Jamie Charles | 2     | 11
Jamie Charles | 0     |  8
Jamie Charles | 3     |  5
Jamie Charles | 1     |  4
Jamie Charles | 5     |  1

但看起来它说有多少目标已经发生。所以正确的结果是(2x11)+(3*5)+(1*4)+(5*1)

此查询的正确语法是什么？

Answer 1

您需要按成员分组，使用sum聚合函数来获取所有目标的总和。您不需要订单

select member, sum(goals), count(*) Total_goal_records
from 
(
select player2_name as member, player1_goals as goals
from results
WHERE player1_id = 2
union all
select player1_name as member, player2_goals as goals
from results
WHERE player2_id = 2 

) AS T

group by member 
order by Total desc;