Question

我有一个像这样的c printf程序

for (r = 0; r <= 100 ; r++) {
        for (c = 0; c <= 100 ; c++) {

             printf("A");
        }
    }

如何编辑代码以便打印5＆＃34; A＆＃34;每行如

＆＃34; AAAAA＆＃34;但多行

Answer 1

检查除法c / 5是否以0的余数返回。

for (r = 0; r <= 20 ; r++) {
    for (c = 0; c <= 20 ; c++) {
        if (c%5 == 0) 
            printf("\r\n");
        printf("A");
    }
}

Answer 2

你只需要将列数减少到5并在每个列周期结束后打印换行符如下：

for (int row = 0; row < 20; ++row) {
    for (int column = 0; column < 5; ++column) {
         printf("A");
    }
    printf("\n");
}

Answer 3

如果打印的字母数是5的倍数，请打印'\n'

void NuBePrint(int rows, int cols, int period, char letter) {
  long count = 0;
  // OP may really want `r < rows` and `c < cols` to print 100x100 rather than 101x101
  for (int r = 0; r <= rows ; r++) {
    for (int c = 0; c <= cols; c++) {
      putchar(letter);
      count++;
      if (count%period == 0) putchar('\n');
    }
  }
  if (count%period != 0) putchar('\n');  // Cope with last line
}

// sample usage 
NuBePrint(100, 100, 5, 'A');

每行打印相同数量的字符

3 个答案: