Question

我有一个json文件 users.json

{
  "Jessica Smith": {
      "name": "Jessica",
      "surname": "Smith",
      "email": "jessica.smith@alias.com",
      "pass": "jessicasmith",
      "sex": "female"
  },
  "Jessica Smith2": {
      "name": "Jessica",
      "surname": "Smith2",
      "email": "jessica.smith2@alias.com",
      "pass": "jessicasmith2",
      "sex": "female"
  },
}

PHP代码

$file = fopen("users.json", a);
if(!$file) die ( "Error");
$value =      "given_name:".$name."\nfamily_name:".$surname."\nemail:".$email."\npass:".$psw."\nsex: ".$type."\n";
fwrite($file, $value);
fclose($file);

使用此代码我只在最后一行之后添加字符串$value，有一种方法可以用json格式转换$value吗？我尝试使用json_encode。

string json_encode(mixed $add[$value]);

但它不起作用。

例如，我想在users.json

中添加Jessica Smith3

  "Jessica Smith3": {
    "name": "Jessica",
    "surname": "Smith3",
    "email": "jessica.smith3@alias.com",
    "pass": "jessicasmith3",
    "sex": "female"
  },

Answer 1

您的$ value无效JSON，文件操作会生成无效的JSON文件。你应该使用

$value =  array(  "given_name"=>$name,
                  "family_name"=>$surname,
                  "email"=>$email,
                  "pass"=>$psw,
                  "sex"=>type);
$file = fopen("users.json", a);
if(!$file) die ( "Error");
$f = json_decode( $file );
$f[] = $value;
$file = json_encode( $f );
fwrite($file, $value);
fclose($file);

如何使用php在json中保存数据

1 个答案: