Question

对不起，即使看了很多视频并且在stackoverflow看起来如此努力，甚至不能正确地找到我的问题（用不同的对象传递参数？）所以我这么新手甚至还没有完全理解，所以在这里我只是展示我的代码。

var Test1 = function(name,gender,job) {
  this.name = name;
  this.gender = gender;
  this.job = job;
this.say = function(name ,gender, job){
    console.log(" sup "+ name +", goodluck in" + job);
  }
}

这是new object：

var budi = new Test1('Budi', 'male', 'developer');
var tono = new Test1('Tono', 'male', 'chef');

我想通过argument传递object：

budi.say(tono);

Answer 1

您可以实现say()

的实施

  this.say = function(person){
    console.log(" sup "+ person.name +", goodluck in" + person.job);
  }

或称之为：

budi.say(tono.name, null, tono.job)

Answer 2

您可能想要改为

this.say = function(/*no arguments here*/ ){
    console.log(" sup "+ this.name +", goodluck in" + this.job);
}

如果为不同的范围指定相同的名称参数，它们将被视为不同的变量。你可以这样做：

var budi = new Test1('Budi', 'male', 'developer');
budi.say();

它将正确显示您在构造函数中使用的字符串。

Answer 3

在say()方法中，从方法参数（我的示例中为name）中读取job和person：

＆＃13;

var Test1 = function(name, gender, job) {
  this.name = name;
  this.gender = gender;
  this.job = job;
  this.say = function(person) {
    console.log("sup " + person.name + ", good luck in " + person.job);
  }
}

var budi = new Test1('Budi', 'male', 'developer');
var tono = new Test1('Tono', 'male', 'chef');

budi.say(tono);

＆＃13;

Answer 4

嗨，请查看这个

＆＃13;

//i change it just for convenient:)
var People = function(name, gender, job) {
  this.name = name;
  this.gender = gender;
  this.job = job;
  /* you want your `say` function to call another People
  so pass People as the arg, Object with name, gender, job, and another say method*/
  this.say = function(p) {
    /* for string i'd like to use backtick(`) for simplicity and less error phone (ex, space, etc)*/
    console.log(`sup ${p.name}, goodluck in ${p.job}`);
  }
}

var budi = new People('Budi', 'male', 'developer');
var tono = new People('Tono', 'male', 'chef');

budi.say(tono);

＆＃13;

javascript在对象中传递参数

4 个答案: