Question

我想以3种颜色绘制圆圈。但在此代码中，用于绘制圆圈，输出没有颜色：

import turtle

window=turtle.Screen()
tess= turtle. Turtle()

import random

def getColor():

    color=random.randint(1,3)
    if color==1:
        color="red"
    elif color==2:
        color=="yellow"
    elif color==3:
        color=="blue"
    return color
print (random.randint(1,3))

def drawFace (x,y):

    tess.penup()
    tess.goto(x+5,y+10)
    tess.circle(10)
    tess.goto(x+15,y+10)
    tess.circle(10)
    tess.pendown()

Answer 1

在getColor()函数中，当它为黄色或蓝色时，您没有分配给color变量 - 您使用的是双等号。这是固定版本：

def getColor():
    color=random.randint(1,3)
    if color==1:
        color="red"
    elif color==2:
        color="yellow"
    elif color==3:
        color="blue"
    return color

其次，你在drawFace()的开头拾起了笔，并且在完成之前从未放下它！这是修复：

def drawFace (x,y):
    tess.penup()
    tess.goto(x+5,y+10)
    tess.pendown()
    tess.circle(10)
    tess.penup()
    tess.goto(x+15,y+10)
    tess.pendown()
    tess.circle(10)

Answer 2

您不需要选择随机数来索引颜色，您可以使用random.choice()直接选择一个。您需要致电GetColor()并应用您通过tess.pencolor()选择的颜色我们也倾向于考虑根据他们的中心定位圈子，但Python龟并不是我们需要（明确地）在你的代码中（隐式地）调整它：

from turtle import Turtle, Screen
import random

RADIUS = 10

def getColor(turtle):
    choice = turtle.pencolor()

    while choice == turtle.pencolor():
        choice = random.choice(["red", "green", "blue"])

    return choice

def drawFace(turtle, x, y):
    turtle.pencolor(getColor(turtle))
    turtle.penup()
    turtle.goto(x, y - RADIUS)
    turtle.pendown()
    turtle.circle(RADIUS)

tess = Turtle()

drawFace(tess, 5, 0)

drawFace(tess, 15, 0)

screen = Screen()

screen.exitonclick()

Python龟绘制随机彩色圆圈

2 个答案: