Java Error java.lang.StringIndexOutOfBoundsException:字符串索引超出范围:0

时间:2016-11-15 03:16:25

标签: java exception

我接到这个例外以及:

  

java.lang.StringIndexOutOfBoundsException:字符串索引超出范围:   0在java.lang.String.charAt(未知来源)at   RandomWalk.matchingChoice(RandomWalk.java:50)at   RandomWalk.main(RandomWalk.java:17)at   sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)at   sun.reflect.NativeMethodAccessorImpl.invoke(未知来源)at   sun.reflect.DelegatingMethodAccessorImpl.invoke(未知来源)at   java.lang.reflect.Method.invoke(未知来源)at   edu.rice.cs.drjava.model.compiler.JavacCompiler.runCommand(JavacCompiler.java:267)

运行此代码时:

import java.util.*;
import java.awt.*;
public class RandomWalk{
  public static final Scanner CONSOLE = new Scanner(System.in);
  public static void main(String[] args){
    System.out.println("Enter Circle Radius (50-400):");
    int radius = CONSOLE.nextInt();
    while (radius < 50 || radius > 400){
      System.out.println("Radius Invalid; Try Again");
      System.out.println("Enter Circle Radius (50-400):");
      radius = CONSOLE.nextInt();
    }
    int diameter = radius*2;
    int panelD = diameter/4;
    System.out.println("Enter Color of Circle (Blue or Green)");
    String colorChoice = CONSOLE.nextLine();
    boolean test = matchingChoice(colorChoice, "blue");
    boolean test2 = matchingChoice(colorChoice, "green");
    while(test2 == false && test == false){
      System.out.println("Invalid Entry Try Again");
      System.out.println("Enter Color of Circle (Blue or Green)");
      colorChoice = CONSOLE.nextLine();
      test = matchingChoice(colorChoice, "blue");
      test2 = matchingChoice(colorChoice, "green");
    }
    if(test == true){
      Color circleColor = Color.BLUE;
    } else {
      Color circleColor = Color.GREEN;
    }
    System.out.println("Enter Color of Walk Path (Orange or Red)");
    colorChoice = CONSOLE.nextLine();
    test = matchingChoice(colorChoice, "orange");
    test2 = matchingChoice(colorChoice, "red");
    while(test2 == false && test == false){
      System.out.println("Invalid Entry Try Again");
      System.out.println("Enter Color of Circle (Orange or Red)");
      colorChoice = CONSOLE.nextLine();
      test = matchingChoice(colorChoice, "orange");
      test2 = matchingChoice(colorChoice, "red");
    }
    if(test == true){
      Color pathColor = Color.ORANGE;
    } else {
      Color pathColor = Color.RED;
    }
  }
  public static boolean matchingChoice(String input, String choice){
    input = input.toLowerCase();
    char fLI = input.charAt(0);
    char fLC = choice.charAt(0);
    if(fLI == fLC){
     return true;
    } else if (input.equals(choice)){
      return true;
    } else {
      return false;
    }
  }
}

错误发生在

之后
System.out.println("Enter Color of Circle (Blue or Green)");

我尝试将nextLine更改为next,这将允许输入,但在输入后会出现相同的错误。任何帮助都会得到很多赞赏,谢谢。

2 个答案:

答案 0 :(得分:0)

你在CONSOLE.nextLine();中犯了一个错误,把它替换为CONSOLE.next(); 并且您的代码将正确运行。

String colorChoice = CONSOLE.next();

将所有CONSOLE.nextLine()替换为CONSOLE.next()

答案 1 :(得分:0)

删除您的扫描仪声明中的最终版本:

public static final Scanner CONSOLE = new Scanner(System.in);

public static Scanner CONSOLE = new Scanner(System.in);

然后您将在Scanner上实例化新的CONSOLE,因为您将在CONSOLE Variable上输入不同的数据类型。

System.out.println("Enter Color of Circle (Blue or Green)");
CONSOLE = new Scanner(); // Instantiate new Scanner on your CONSOLE variable
colorChoice = CONSOLE.nextLine();
希望它有所帮助。