我想做类似的事情:
class A(Resource):
@dec(from_file=A.docpath)
def get(self):
pass
class B(A):
docpath = './docs/doc_for_get_b.json'
class C(A):
docpath = './docs/doc_for_get_c.json'
def dec(*args, **kwargs):
def inner(f):
docpath = kwargs.get('from_file')
f.__kwargs__ = open(path, 'r').read()
return f
return inner
将调用的函数为B.get
和C.get
,而不是A.get
。
如何访问docpath
或class B
中定义的自定义属性class C
,并将其传递给get
中class A
函数的装饰器?< / p>
当前解决方案:将装饰器放在每个派生类上......
class A(Resource):
def _get(self):
pass
class B(A):
@dec(from_file='./docs/doc_for_get_b.json')
def get(self):
return self._get()
class C(A)
@dec(from_file='./docs/doc_for_get_c.json')
def get(self):
return self._get()
这可行,但与前一代码中的类的单行声明相比,它非常难看。
答案 0 :(得分:1)
要在装饰器内访问类的属性很简单:
def decorator(function):
def inner(self):
self_type = type(self)
# self_type is now the class of the instance of the method that this
# decorator is wrapping
print('The class attribute docpath is %r' % self_type.docpath)
# need to pass self through because at the point function is
# decorated it has not been bound to an instance, and so it is just a
# normal function which takes self as the first argument.
function(self)
return inner
class A:
docpath = "A's docpath"
@decorator
def a_method(self):
print('a_method')
class B(A):
docpath = "B's docpath"
a = A()
a.a_method()
b = B()
b.a_method()
一般情况下,我发现使用多层装饰器,即装饰工厂功能,可以创建装饰,例如你使用的装饰器,如:
def decorator_factory(**kwargs):
def decorator_function(function):
def wrapper(self):
print('Wrapping function %s with kwargs %s' % (function.__name__, kwargs))
function(self)
return wrapper
return decorator_function
class A:
@decorator_factory(a=2, b=3)
def do_something(self):
print('do_something')
a = A()
a.do_something()
在阅读代码时难以理解并且不易理解,因此我倾向于使用类属性和通用超类方法来支持许多装饰器。
因此,在您的情况下,不要将文件路径作为参数传递给装饰器工厂,而是将其设置为派生类的类属性,然后在超类中编写一个读取来自实例类的class属性。