Question

我有一个需要执行1000次的查询。每次我需要在该查询中增加两个过滤器值。

select min(a), min(bo
from(select*
from(select unmatchedpow.id, unmatchedpow.ut_sec-difference AS A, unmatchedpow.ut_sec-difference AS B
from(select*
from(select unmatchedpow.ut_sec-unmatchedsaaf.ut_sec AS difference,*
from(select*from unmatchedpow, unmatchedsaaf 
order by unmatchedpow.id))))
where unmatchedpow.id between 0 and 1)

因此，每次迭代时，语句参数之间的最后一个增加1，即1到2之间，然后是2到3之间......直到999和1000.

有什么方法可以做到这一点并存储结果吗？

Answer 1

创建一个包含0到999的数字的表格，并加入该表格以获取BETWEEN测试的值。

SELECT n.num, min(x.a), min(x.b)
from number_table AS n
LEFT JOIN (select*
    from(select unmatchedpow.id, unmatchedpow.ut_sec-difference AS A, unmatchedpow.ut_sec-difference AS B
        from(select*
            from(select unmatchedpow.ut_sec-unmatchedsaaf.ut_sec AS difference,*
                from(select*from unmatchedpow, unmatchedsaaf)))) AS x
ON x.id BETWEEN n.num AND n.num+1

如何在SQL中执行迭代

1 个答案: