Question

大家好我想打印函数xcode_version的输出只有版本号，我的代码在这里包含2个错误，第一个是：print（＆＃34; Xcode版本：％s％s％s＆＃34;％（G，R）xcode_version（））
SyntaxError：语法无效第二个是，当执行命令时，它只是按照它应该做的那样grep版本号（Xcode 7.0.1）但它打印了hole xcodebuild -version命令，结果是：Xcode 7.0.1 Build version 7A1001 这2个错误的解决方案？

    #!/usr/bin/env python2.7
#
#Putty-On-Osx By Fedy Wesleti
import sys
import os
import subprocess

G = '\033[92m' #green
Y = '\033[93m' #yellow
B = '\033[94m' #blue
R = '\033[91m' #red

def xcode_version():
    try:
        xcode = subprocess.call(["xcodebuild","-version","&","grep","xcode"])
        print(xcode)
    except OSError as e:
        if e.errno == os.errno.ENOENT:
            print("Not Installed")
        else:
            # Something else went wrong while trying to run `wget`
            raise


print("Xcode Version : %s%s%s"%(G,R)xcode_version())

打印长函数的输出 - python

0 个答案: