Question

我正在使用PHP的网站上工作，我希望在单击按钮时更新数据库。但由于某些原因，无论何时加载页面，代码都会运行，我不希望这样，因为它可能会弄乱整个代码。如何让脚本自动停止运行？

<?php
    ob_start();
    session_start();
    include_once 'dbconnect.php';

    if(!isset($_SESSION['user'])) {
        header("Location: index.php");
        exit;
    }

    $condition = empty($_POST['sender']) || empty($_POST['reciever']);
    if ($condition) {
        die; // if your post data is empty PHP will no longer be executed
    }

    $res= "SELECT * FROM users WHERE userId=".$_SESSION['user'];
    $mysqli->query($con, $res); // you are doing nothing with it in your code, why?
    $name = $_POST['sender'];       
    $name = $_POST['reciever'];

    $query = "UPDATE users SET userCoins = userCoins + 1  WHERE userName='Morgan'";
    $res = $mysqli->query($con, $query);
    if ($res) {
       $error = "Success!";
    } else {
       $error = "Something Went Wrong!";
    }
?>
<!DOCTYPE html>
<html>
    <?php header("Access-Control-Allow-Origin: http://www.py69.esy.es"); ?>
    <head>
        <title>ServiceCoin</title>
        <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
        <link rel="stylesheet" href="assets/css/bootstrap.min.css" type="text/css"  />
        <link rel="stylesheet" href="scripts/home/index.css" />
    </head>
    <body>
        <ul>
            <li><a href="#" class="a">ServiceCoin.com(image)</a></li>
            <li><a href="logout.php?logout" class="a">Sign Out</a></li>
            <li><a href="#" class="a">Contact</a></li>
            <li><a href="#" class="a">Get Service Coins</a></li>
            <li><a href="#" class="a">News</a></li>
            <li><a href="settings.php" class="a">Settings</a></li>
            <li><a href="#" class="a">Referrals</a></li>
            <li><a href="service.php" class="a">Services</a></li>
            <li><a href="home.php" class="a">Home</a></li>
        </ul>
        <br /><br />
        <center>
        <h3>Welcome, <?php echo $userRow['userName']; ?>. You Currently Have <span id="services"><?php echo $userRow['userCoins']; ?></span> Service Coins</h3>
        <form method="post" action="<?php echo htmlspecialchars($_SERVER['PHP_SELF']); ?>" autocomplete="off">
            <div class="form-group">
                <div class="input-group">
                    <span class="input-group-addon"><span class="glyphicons glyphicons-lock"></span></span>
                    <input type="text" name="sender" class="form-control" placeholder="Enter Your Wallet Key" value="<?php echo $row['userCoins']; ?>" maxlength="15" />
                    <span class="text-danger"><?php echo $error; ?></span>
                </div>
                <div class="input-group">
                    <span class="input-group-addon"><span class="glyphicons glyphicons-lock"></span></span>
                    <input type="text" name="reciever" class="form-control" placeholder="Enter The Recievers Wallet Key" value="<?php echo $row['userCoins']; ?>" maxlength="15" />
                    <span class="text-danger"><?php echo $error; ?></span>
                </div>

            </div>
            <div class="form-group">
                <button type="submit" class="btn btn-block btn-primary" name="send">Sign Up</button>
            </div>
        </form>
        </center>
    </body>
</html>
<?php ob_end_flush(); ?>

更新

我的页面现在完全是白色的。

class Hello_World
{
    public:
        void hello(size_t number){
            cout << "hello " << number << endl;
        }
};


template<size_t SIZE, class T>
void foo()
{
    T t;
    t.hello(SIZE);
    foo<SIZE-1, Hello_World>();
}

template<class T>
void foo<0,T>()
{
    cout << "end." << endl;
}

int main()
{
    foo<4,Hello_World>();
}

Answer 1

您应该使用MySQLi。关于mysql_*为什么不能阅读here

<强>解决方案

您的代码如下所示：

$mysqli = new mysqli("localhost", "my_user", "my_password", "table_name"); // here you will need your connection data, you can store it in dbconnect.php.

// if session is not set this will redirect to login page    
if(!isset($_SESSION['user'])) {
    header("Location: index.php");
    exit;
}

$condition = empty($_POST['sender']) || empty($_POST['reciever']);
if (!$condition) {
    $res= "SELECT * FROM users WHERE userId=".$_SESSION['user'];
    $mysqli->query($res); // you are doing nothing with it in your code, why?
    $name = $_POST['sender'];       
    $reciever = $_POST['reciever'];

    $query = "UPDATE users SET userCoins = userCoins + 1  WHERE userName='Morgan'";
    $res = $mysqli->query($query);
    if ($res) {
        $error = "Success!";
    } else {
        $error = "Something Went Wrong!";
        echo "Error: ".$mysqli->error; // here you can check your errors
    }
}

<强>手册

有关MySQLi的更多信息，请参阅PHP Manual

PHP代码在没有单击按钮的情况下运行

1 个答案: