Question

CODE：

    class matrix():

    row=0
    colum=0
    def __init__(self,x,y):
    self.m=[]
        self.row=x
        self.colum=y
        #Makes a empty matrix of size x*y
        for i in range(self.row):
            self.m.append([])
            for j in range(self.colum):
                self.m[i].append(int(raw_input("Enter element")))
#To diplay the matrix
def display(x):
    k=x.m
    for i in range(0,x.row):
            for j in range(0,x.colum):
                k[i][j]=x.m[i][j]
    return k
row1=int(raw_input("Enter Number of rows of 1st Matrix"))
colum1=int(raw_input("Enter Number of colume of 1st Martrix"))
matrix1=matrix(row1,colum1)
print "1st Matrix:",display(matrix1) # displaying the first matix before adding elements
row2=int(raw_input("Enter Number of rows of 2nd Matrix"))
colum2=int(raw_input("Enter Number of colume of 2nd Martrix"))
matrix2=matrix(row2,colum2)
print "Matrix 2:",display(matrix2) #displaying the second matrix before adding elements

输出：

Enter Number of rows of 1st Matrix2
Enter Number of colume of 1st Martrix2
Enter element11
Enter element22
Enter element33
Enter element44
1st Matrix: [[11, 22], [33, 44]]
Enter Number of rows of 2nd Matrix2
Enter Number of colume of 2nd Martrix3
Enter element1
Enter element2
Enter element3
Enter element4
Enter element5
Enter element6
Matrix 2: [[11, 22, 1, 2, 3], [33, 44, 4, 5, 6], [], []]

我在python 2.7中编写了以下代码，我期望发生的是使用类矩阵的构造函数创建两个给定大小的matix。如输出中所示，对象即矩阵1和矩阵2共享相同的列表m。我们默认情况下不应该存储两个单独列表。预期矩阵2是

[[1,2,3],[4,5,6]]

Answer 1

您可以将def display函数移动到类本身中。这将成为您从matrix对象调用的方法，即matrix1.display()。变量m，row和column当前未保存在matrix对象中。请尝试下面的代码。

class matrix(object):
    def __init__(self,x,y):
        self.m = []
        self.row = x
        self.colum = y
        #Makes a empty matrix of size x*y
        for i in range(self.row):
            self.m.append([])
            for j in range(self.colum):
                self.m[i].append(int(raw_input("Enter element ({},{}): ".format(i,j))))

    #To diplay the matrix
    def display(self):
        for r in self.m:
            print(r)


>>> matrix1 = matrix(2,2)
Enter element (0, 0): 11
Enter element (0, 1): 22
Enter element (1, 0): 33
Enter element (1, 1): 44

>>> matrix1.display()
[11, 22]
[33, 44]

两个对象共享相同的列表

1 个答案: