我尝试使用以下代码,但无法删除逗号。请帮忙。
Sub removelastcommas()
Dim i As Integer, str As String
str = Range("A1")
For i = Len(str) To 1
If Mid(str, i, 1) <> "," Then
Exit For
End If
Next
Range("b1") = Left(str, i)
End Sub
答案 0 :(得分:2)
这将删除字符串中的最后一个逗号:
Sub removelastcommas()
Dim i As Integer, str As String
str = Range("A1")
For i = Len(str) To 1 Step -1
If Mid(str, i, 1) = "," Then
Range("B1").Value = Left(str, i - 1) & Mid(str, i + 1)
Exit Sub
End If
Next i
End Sub
答案 1 :(得分:2)
使用public class FooUpdatesHandler extends ConcurrentTextWebSocketHandler {
// ConcurrentTextWebSocketHandler taken from https://github.com/RWTH-i5-IDSG/BikeMan (Apache License version 2.0)
private static final Logger logger = LoggerFactory.getLogger(FooUpdatesHandler.class);
private static final ConcurrentHashMap<String, ConcurrentHashMap<String, WebSocketSession>> fooSubscriptions =
new ConcurrentHashMap<>();
public static void sendFooToSubscribers(Foo foo) {
Map<String, WebSocketSession> sessionMap = fooSubscriptions.get(foo.getId());
if (sessionMap != null) {
String fooJson = null;
try {
fooJson = new ObjectMapper().writeValueAsString(foo);
} catch (JsonProcessingException ignored) {
return;
}
for (WebSocketSession subscription : sessionMap.values()) {
try {
logger.info("[fooId={} sessionId={}] Sending foo...", foo.getId(), subscription.getId());
subscription.sendMessage(new TextMessage(fooJson));
logger.info("[fooId={} sessionId={}] Foo send.", foo.getId(), subscription.getId());
} catch (IOException e) {
logger.error("Socket sendFooToSubscribers [fooId={}], exception: ", foo.getId(), e);
}
}
}
}
}
函数(不使用循环)的另一个选项是:
InStrRev