var numbersDetail = List is type of ContactDetail()
let predicate = NSPredicate(format: ContactDetail.NUMBER + " = %@", formattedNumber!)
let realmContactDetail = numbersDetail.filter(predicate).first
获取错误：
抛出RLMException（“此方法只能在RLMArray上调用 从RLMRealm“）中检索的实例;
答案 0 :(得分：1)
如果在将父对象添加到{之前尝试对Realm Swift List对象（实际上是Objective-C RLMArray对象）执行查询，则会发生此错误{1}}。
Realm简而言之，在执行该查询之前，您需要确保class Person: Object {
dynamic var name = ""
dynamic var picture: NSData? = nil // optionals supported
let dogs = List<Dog>()
}
let dog = Dog()
dog.name = "Rex"
let person = Person()
person.dogs.append(dog)
let rex = person.dogs.filter("name == 'Rex'") // QUERY WILL TRIGGER EXCEPTION AT THIS POINT
let realm = try! Realm()
try! realm.write {
realm.add(person)
}
let rex = person.dogs.filter("name == 'Rex'") // Query will now work as expected
属于numbersDetail。您可以通过选中Realm。