Question

for (int i = 0; i < 6; i++) {
        lineOne[i] = Integer.parseInt(JOptionPane.showInputDialog(null,"");

        if (lineOne[i] > 47 || lineOne[i] < 1)//Number also have to be inside these parameters 
            JOptionPane.showMessageDialog(null, "Please try again!!!");
            lineOne[i] = Integer.parseInt(JOptionPane.showInputDialog(null, ""));
        }
    }

Answer 1

使用Set而不是使用数组。

示例：

Set<Integer> numbers=new HashSet<>();

然后将数字添加到集合中。它不允许重复。

Answer 2

问题在于你的if语句。如果输入的值超出1-47范围，则写入代码的方式，您再次询问该值。但是，如果再次给出“不正确”的值，则将其保留在数组中并返回到for循环的顶部。

试试这个。

for (int i = 0; i < 6; i++) {
        lineOne[i] = Integer.parseInt(JOptionPane.showInputDialog(null,"");

        while (lineOne[i] > 47 || lineOne[i] < 1) { //Number also have to be inside these parameters 
            JOptionPane.showMessageDialog(null, "Please try again!!!");
            lineOne[i] = Integer.parseInt(JOptionPane.showInputDialog(null, ""));
        }
    }

Answer 3

    boolean b = true;
    int[] lineOne = new int[6];
    for (int i = 0; i < 6; i++) {
        b = true;
        int k = Integer.parseInt(JOptionPane.showInputDialog(null, ""));
        for (int j : lineOne) {
            if (k == j) {
                System.out.println("error");
                b = false;
                break;
            }
        }
        if (b && k < 47 && k > 1) {
            lineOne[i] = k;
        } else {
            JOptionPane.showInputDialog(null, "Duplicate value or value out of bounds.");
            i--;
        }
    }

这是我能想到的最佳方式。 boolean确定值是否已存在

如何阻止在数组中输入重复值？

3 个答案: