Python Hangman代码

Question

对于我的计算机科学控制评估，我被要求用Python创建一个Hangman游戏。但是，在创建游戏时，会出现一条错误消息，指出不在我的代码中的内容。

Traceback (most recent call last):
File "Z:\Documents\hangman.py", line 40, in <module>
generated_word = random.choice(random)
 File "Q:\Pywpygam.001\Python3.2.3\lib\random.py", line 249, in choice
 i = self._randbelow(len(seq))
TypeError: object of type 'module' has no len()

我没有在代码中看到任何错误，也没有说明错误。这是我的代码：

import time
print('Lets play hangman')
print("""
       _______
       |    |
       |    O
       |    |
       |  \- -/
       |    |
       |   / \\
       |  /   \\
   ____|____
   \n""")

print("""
you get 7 lives to guess the letters in the word. if you guess
incorrectly more of the hangman will appear and you lose a life. when you have
used your 7 lives, the man will have hung and you will have lost. If you guess a
correct letter, it will be show and if you guess the word without using the 7
turns, you win!
\n""")

easy_words = ['string', 'loop', 'python', 'print', 'run']
medium_words = ['module', 'input', 'logic', 'output']
hard_words = ['graphics window', 'variable', 'iteration', 'modules']
random_words = ['string', 'loop', 'python', 'print', 'run', 'graphics window', 'variable', 'iteration', 'modules', 'module', 'input', 'logic', 'output    ']
time.sleep(2)
print ("What level would you like to play at? Easy, Medium or Hard or Random?")
level_of_difficulty = input()
time.sleep(2)
print ("The program is now generating your word...")
if level_of_difficulty == 'Easy':
    generated_word = random.choice(easy_words)
elif level_of_difficulty == 'Medium':
    generated_word = random.choice(medium_words)
elif level_of_difficulty == 'Hard':
    generated_word = random.choice(hard_words)
elif level_of_difficulty == 'Random':
    generated_word = random.choice(random_words)
else:
    generated_word = random.choice(random_words)
guessed = ''

lives = 7


while lives > 0:

    missed = 0
    print()
    for letter in generated_word:
        if letter in guessed:
            print (letter,end=' ')
        else:
            print ('_',end=' ')
            missed = missed + 1
    if missed == 0:
        print ('\n\nYou win!')  
        quit()
        break
    guess=input("please guess a letter:")

    guessed = guessed + guess
        if guess not in generated_word:

            print ('\n that letter is not in this word, your lives have been decreased by 1.')
        print ('please try another letter.')
        lives = lives - 1 
        missed = missed + 1

        print('your new lives value is')

        print(lives)

        if lives < 7:
            print('''   _______
   |    |   ''')
            if lives < 6:
                print('   |    O    ') 
            if lives < 5:            
                print('   |    |    ')
            if lives < 4:
                print('   |  \- -/  ')
            if lives < 3: 
                print('   |    |    ')
            if lives < 2:
                print('   |   / \\  ')
            if lives < 1:
                print('   |  /   \\ ')
            if lives == 0:
             print('___|___      ')

             print('GAME OVER! You have run out of lives and lost the game')
             print('the secret word was')
             print(generated_word)
             quit()

我要做的是让它生成的单词显示在带有_的窗口中，当正确猜出字母时，相应的_将填充字母。 任何想法将不胜感激！

Answer 1

我认为这些行是错误的：

print

您正在传递模块＆＃34;随机＆＃34;作为参数。我认为你应该传递变量＆＃34; random_words＆＃34;？

Answer 2

我看到我做错了什么，谢谢你指出

generated_word = random.choice(random) 

位，但我也在

上看到了

while lives > 0:

    missed = 0
    print()
    for letter in generated_word:
        if letter in guessed:

我犯了一个拼写错误。 谢谢大家！