我已经创建了一个Util类来打开和关闭像这样的
进度对话框Utils.java
public class Utils {
private static Utils util;
private Typeface typeface;
private ProgressDialog progressDialog;
public static Utils getInstance(){
if(util == null){
util = new Utils();
}
return util;
}
public void showProgressDialog(Activity activity){
if(progressDialog != null && progressDialog.isShowing()){
return;
}
if(progressDialog == null ) {
progressDialog = new ProgressDialog(activity);
}
progressDialog.setMessage("Loading...");
progressDialog.setProgressStyle(ProgressDialog.STYLE_SPINNER);
progressDialog.setCancelable(false);
progressDialog.show();
}
public void closeProgressDialog(){
try {
if (progressDialog != null && progressDialog.isShowing()) {
progressDialog.dismiss();
progressDialog = null;
}
}catch(Exception e){
e.printStackTrace();
}
}
}
然后我在加载数据之前调用showProgressDialog,在加载数据之后调用closeProgressDialog。像这样
能力代码
public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.fragment_dashboard,container,false);
activity = getActivity();
ButterKnife.bind(this,view);
init();
return view;
}
private void init() {
Utils.getInstance().showProgressDialog(activity);
getPatientsList();
//in response i am calling closeProgressDialog();
}
public void onPatientListResponse(String response){
Utils.getInstance().closeProgressDialog(); // raises exception here
}
但它在closeProgressDialog();
中引发异常java.lang.IllegalArgumentException: View=com.android.internal.policy.PhoneWindow$DecorView{f7fd12e V.E...... R......D 0,0-1024,232} not attached to window manager
答案 0 :(得分:2)
试试这个,
无论如何你要检查progressDialog是否已经显示是否只是返回控件。而不是解雇progressDialog并创建一个新实例。因为旧的progressDialog可能以不同的上下文开始。
public void showProgressDialog(Activity activity){
if(progressDialog != null && progressDialog.isShowing()){
progressDialog.dismiss();
progressDialog = null;
}
if(progressDialog == null ) {
progressDialog = new ProgressDialog(activity);
}
progressDialog.setMessage("Loading...");
progressDialog.setProgressStyle(ProgressDialog.STYLE_SPINNER);
progressDialog.setCancelable(false);
if(!activity.isFinishing())
progressDialog.show();
}
答案 1 :(得分:1)
public void showProgressDialog(Activity activity){
if(progressDialog != null){ // Ensure it's not null
if(progressDialog.isShowing()) // if it's showing than return.
return;
}else{
//It will create an instance of new object.
progressDialog = new ProgressDialog(activity);
}
progressDialog.setMessage("Loading...");
progressDialog.setProgressStyle(ProgressDialog.STYLE_SPINNER);
progressDialog.setCancelable(false);
progressDialog.show();
}
答案 2 :(得分:0)
您甚至没有初始化进度条,而是在尝试检查它是否显示...
此处您还没有初始化您的进度条,但由于您的条件是&& (AND),编译器应检查两者并发现progressDialog为null,因此没有isShowing方法...
if(progressDialog != null && progressDialog.isShowing()){
return;
}
--------------------------------------------------
public void showProgressDialog(Activity activity){
if(progressDialog == null ) {
progressDialog = new ProgressDialog(activity);
}
progressDialog.setMessage("Loading...");
progressDialog.setProgressStyle(ProgressDialog.STYLE_SPINNER);
progressDialog.setCancelable(false);
progressDialog.show();
}
一个建议是使用上下文而不是进度条的活动。
干杯!
答案 3 :(得分:0)
我以前遇到过这个问题,并使用下面的代码解决了。
private boolean isDialogViewAttachedToWindowManager() {
if (dialog.getWindow() == null) return false;
View decorView = progressDialog.getWindow().getDecorView();
return decorView != null && decorView.getParent() != null;
}
或尝试以下解决方案。
if (pDialog instanceof Activity && !((Activity) mContext).isFinishing())
pDialog.show();