Question

我在php下面有一个多维数组。

   $resultdata[0] = array(
                            "daynumber" =>  15,
                            "dayname"   =>'Tue', 
                            "infomation"    =>  array('baller', 'ROller')
                            );  
    $resultdata[1] = array(
                            "daynumber" =>  15,
                            "dayname"   =>'Tue', 
                            "infomation"    =>  array('nomal', 'Goildt')
                            );  
    $resultdata[2] = array(
                            "daynumber" =>  24,
                            "dayname"   =>'Thur', 
                            "infomation"    =>  array('Volley', 'Foller')
                            );

我想结合相似的日期来形成以下结果。

$resultdata[0] = array(
                        "daynumber" =>  15,
                        "dayname"   =>'Tue', 
                        "infomation"    =>  array('baller', 'ROller'), array('nomal', 'Goildt')
                        );  
$resultdata[1] = array(
                        "daynumber" =>  24,
                        "dayname"   =>'Thur', 
                        "infomation"    =>  array('Volley', 'Foller')
                        );

提前完成

我尝试使用此代码，但它要求我将数组转换为我不想要的字符串

function combineAndIgnore($result_arr){
    $arr = array();
    foreach($result_arr as $val){
          $item = $val[$key];     
          foreach($val as $k=>$v){
              $arr[$item][$k][] = $v;
          }
    }

    // Combine unique entries into a single array
    // and non-unique entries into a single element
    foreach($arr as $key=>$val){
        foreach($val as $k=>$v){
            $field = array_unique($v);
            if(count($field) == 1){
                $field = array_values($field);
                $field = $field[0];
                $arr[$key][$k] = $field;
            } else {
                $arr[$key][$k] = $field;
            }
        }
    }
    return $arr;
}

Answer 1

我屈服于转换为sting选项，无论如何都是

            Array
(
    [0] => Array
        (
            [daynumber] => 15
            [dayname] => Tue
            [infomation] => Array
                (
                    [0] => Array
                        (
                            [0] => baller
                            [1] => ROller
                            [2] => 
                            [3] => gtk
                        )

                    [1] => Array
                        (
                            [0] => nomal
                            [1] => Goildt
                        )

                )

        )

    [1] => Array
        (
            [daynumber] => 24
            [dayname] => Thur
            [infomation] => Array
                (
                    [0] => Volley
                    [1] => Foller
                )

        )

)

RESULT

sw-precache

Answer 2

以下是您的唯一用例的快速解决方案，您也可以使用Quick-T3st here：

<?php

    $strJson    = '[
                        {
                            "daynumber"     :15,
                            "dayname"       :"Tue",
                            "infomation"    :["baller","ROller"]
                        },
                        {
                            "daynumber"     :15,
                            "dayname"       :"Tue",
                            "infomation"        :["nomal","Goildt"]
                        },
                        {
                            "daynumber"     :24,
                            "dayname"       :"Thur",
                            "infomation"    :["Volley","Foller"]
                        }
                    ]';


    function arrayBlend($jsonData){
        $resultData = json_decode($jsonData, true);
        $arrAll     = [];

        foreach($resultData as $data){
            if(is_array($data)){
                $arrAll[]   = $data;
            }
        }

        foreach($arrAll as $iCount=>&$arr){
            $dayNum     = $arr['daynumber'];
            $dayName    = $arr['dayname'];
            $prev       = ($iCount>0) ? $arrAll[$iCount-1] : null;
            if($prev['daynumber'] == $dayNum && $prev['dayname'] == $dayName){
                $arr['infomation'] = [ $prev['infomation'], $arr['infomation']];
                unset($arrAll[$iCount-1]);
            }
        }
        return $arrAll;
    }

    var_dump( arrayBlend($strJson) );

以上var_dump()：

    array:2 [
      1 => array:3 [
        "daynumber" => 15
        "dayname" => "Tue"
        "infomation" => array:2 [
          0 => array:2 [
            0 => "baller"
            1 => "ROller"
          ]
          1 => array:2 [
            0 => "nomal"
            1 => "Goildt"
          ]
        ]
      ]
      2 => array:3 [
        "daynumber" => 24
        "dayname" => "Thur"
        "infomation" => array:2 [
          0 => "Volley"
          1 => "Foller"
        ]
      ]
    ]

结合多维数组并忽略

2 个答案: