Question

我正在尝试开发一个应用程序，其中有三种帐户类型学生登录，导师登录，机构登录我开发了三个名为的应用程序学生，导师和学院，但当我在学生应用程序中注册用户，然后通过该用户名我也可以登录到导师应用程序。那么如何管理所有类型的账户..

forms.py文件

class UserRegisterForm(forms.ModelForm):
    #Student_Name= forms.CharField(max_length=300)
    email = forms.EmailField(label="Email Address")
    email2 = forms.EmailField(label="Confirm Email")
    password = forms.CharField(widget=forms.PasswordInput)
    password2 = forms.CharField(widget=forms.PasswordInput, label="Confirm Password")
    class Meta:
        model = User
        fields = ['username','password','password2','email','email2']

    def clean_password2(self):
        print(self.cleaned_data)
        password = self.cleaned_data.get('password')
        password2 = self.cleaned_data.get('password2')
        print(password, password2)
        if password != password2:
            raise forms.ValidationError("Passwords don't match")
        else:
            return password

    def clean_email2(self):
        print(self.cleaned_data)
        email = self.cleaned_data.get('email')
        email2 = self.cleaned_data.get('email2')
        print(email, email2)
        if email != email2:
        raise forms.ValidationError("Email addresses don't match")
        email_qs = User.objects.filter(email=email)
        if  email_qs.exists():
            raise forms.ValidationError("This email has already been registered")
        else:
            return email


class UserLoginForm(forms.Form):
    username = forms.CharField()
    password = forms.CharField(widget=forms.PasswordInput)

    def clean(self, *args, **kwargs):
        username = self.cleaned_data.get("username")
        password = self.cleaned_data.get("password")

        #user_qs = User.objects.filter(username=username)
        #if user_qs.count() == 1:
        #   user = user_qs.first()
        if username and password:
            user = authenticate(username=username, password=password)
            if not user:
                raise forms.ValidationError("This user does not exist")
            if not user.check_password(password):
                raise forms.ValidationError("Incorrect password")
            if not user.is_active:
                raise forms.ValidationError("This user is no longer active")
            return super(UserLoginForm, self).clean(*args, **kwargs)

views.py

def register_view(request):
    print(request.user.is_authenticated())

    form = UserRegisterForm(request.POST or None)
    if form.is_valid():
        user = form.save(commit=False)
        password = form.cleaned_data.get('password')
        user.set_password(password)
        user.save()
        new_user = authenticate(username=user.username, password=password)
        login(request, new_user)
        return render(request, 'app/register_sucessfull.html',{})

    context = {
        "form": form,

    }
    return render(request, "app/register.html", context)

def login_view(request):
    print(request.user.is_authenticated())
    w="Welcome"
    title = "Login"
    form = UserLoginForm(request.POST or None)
    if form.is_valid():
        username = form.cleaned_data.get("username")
        password = form.cleaned_data.get("password")
        user = authenticate(username=username, password=password)
        login(request, user)
        return render(request,'app/index1.html',{'username':username,'w':w})
        #return redirect('student_view')


    return render(request, "app/login.html", {"form":form, "title":title})

所有剩余应用中的相同代码

Answer 1

我假设您希望通过角色区分用户。但你做的不是正确的方法。 Django有权限和组来解决这个问题。主动使用Django权限以显示或隐藏页面上的某些元素。行动也一样。相信我，您不希望为系统中的每个角色创建自定义身份验证位置。

创建Students，Tutor，Institute django群组，然后根据权限更改您登录时显示的内容。这是唯一解决问题的Django方式

Answer 2

您应该将Django auth Group用于三个不同的组，即学生，教师和学院，并为不同的登录分配不同的权限。您可以创建一个名为Permissions的新模型，并为所有gropus添加不同的permisions，请点击此处：

from django.contrib.auth.models import User, Group, Permission
from django.contrib.contenttypes.models import ContentType

content_type = ContentType.objects.get(app_label='yourapp', model='Your_model')
permission = Permission.objects.create(codename='can_login',
                                       name='Can login as tutor ',
                                       content_type=content_type)
user = User.objects.get(username='some_name')
group = Group.objects.get(name='tutor')
group.permissions.add(permission)
user.groups.add(group)

进一步阅读，Read from here.

在django

2 个答案: